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adell [148]
4 years ago
12

Name the following compound:

Chemistry
1 answer:
Tems11 [23]4 years ago
6 0

Answer:

The answer is 1-butene

Explanation:

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Describe how a mole ratio is correctly expressed when it is used to solve a stoichiometry problem
notka56 [123]
Basically stoichiometry is the measurement of elements, that is, the study of chemical quantities consumed or produced in a chemical reaction. When we are performing it we are using a special chemical counting unit: the mole, a unit of measurement, and one mole of a substance contains 6.022 * 10^23 particles. Now mole ratio is defined as the ratio of moles of one substance to the moles of another substance in a balanced equation. <span>If we are looking for the mole ratio between two substances, we need to look at the balanced equations</span> for the coefficients in front of the substances you are interested in.
This should be your guiding mantra for doing stoichiometry problems!
3 0
3 years ago
When the pressure of a gas doubt, does the volume:
SVEN [57.7K]

Answer:

it will halves

Explanation:

if the volume is doubled then the pressure is halves.

8 0
3 years ago
A hamburger containing 335.4 kcal of energy was combusted in a bomb calorimeter with an unknown heat capacity. The temperature o
Zielflug [23.3K]

Answer:

Cv_{calorimeter}=18.4kcal/K

Explanation:

Hello!

In this case, since the combustion of the hamburger released 335.4 kcal of energy and that energy is received by the calorimeter, we can write:

Q_{hamburguer}=-Q_{calorimeter}

And the heat of the calorimeter is written in terms of the temperature change and the calorimeter constant:

Q_{hamburguer}=-Cv_{calorimeter}\Delta T

Thus, given the released heat by the hamburger due to its combustion and the temperature change, Cv for the calorimeter turns out:

Cv_{calorimeter}=\frac{-Q_{hamburguer}}{\Delta T} =\frac{-(-335.4kcal)}{18.2K}\\\\Cv_{calorimeter}=18.4kcal/K

Best regards!

4 0
3 years ago
¿¿¿Alguien sabe que sustancias no concuerdan con el modelo de Arrhenius??? Es urgente, ayuden por favor
Kay [80]
Twjegnefnwfnnegengefbefb no se
8 0
4 years ago
ASAP PLEASEE A certain amount of Argon has 2.4x10^24 atoms. Going backwards from Atoms to Grams, how many grams of Ar would that
Dima020 [189]

The required mass of argon in given number of atoms of argon is 155.61 grams.

<h3>What is Avogadro's number?</h3>

Avogadro's number is the number of atoms which are present in 1 mole of any substance and it is equal to 6.022×10²³.

Relation between the mass and moles of any substance will be represented as:

  • n = W/M, where
  • W = given mass
  • M = molar mass

So, moles of argon will be calculated by using given number of atoms as:

Moles = 2.4×10²⁴ atoms / 6.022×10²³ atoms per mole

Moles = 3.9 moles

Now mass will be:

W = (3.9mol)(39.9g/mol) = 155.61 g

Hence required mass of argon is 155.6g.

To know more about Avogadro's number, visit the below link:

brainly.com/question/1513182

#SPJ1

8 0
2 years ago
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