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zysi [14]
2 years ago
11

ASAP PLEASEE A certain amount of Argon has 2.4x10^24 atoms. Going backwards from Atoms to Grams, how many grams of Ar would that

be?
Chemistry
1 answer:
Dima020 [189]2 years ago
8 0

The required mass of argon in given number of atoms of argon is 155.61 grams.

<h3>What is Avogadro's number?</h3>

Avogadro's number is the number of atoms which are present in 1 mole of any substance and it is equal to 6.022×10²³.

Relation between the mass and moles of any substance will be represented as:

  • n = W/M, where
  • W = given mass
  • M = molar mass

So, moles of argon will be calculated by using given number of atoms as:

Moles = 2.4×10²⁴ atoms / 6.022×10²³ atoms per mole

Moles = 3.9 moles

Now mass will be:

W = (3.9mol)(39.9g/mol) = 155.61 g

Hence required mass of argon is 155.6g.

To know more about Avogadro's number, visit the below link:

brainly.com/question/1513182

#SPJ1

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The question is incomplete, here is the complete question:

Calculate the volume in liters of a 0.13 M potassium dichromate solution that contains 200. g of potassium dichromate . Round your answer to 2 significant digits.

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<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

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We are given:

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