Question

A hamburger containing 335.4 kcal of energy was combusted in a bomb calorimeter with an unknown heat capacity. The temperature of the water bath increased by 18.2 K. What's Cv for this calorimeter

Answer 1

Answer:

$Cv_{calorimeter}=18.4kcal/K$

Explanation:

Hello!

In this case, since the combustion of the hamburger released 335.4 kcal of energy and that energy is received by the calorimeter, we can write:

$Q_{hamburguer}=-Q_{calorimeter}$

And the heat of the calorimeter is written in terms of the temperature change and the calorimeter constant:

$Q_{hamburguer}=-Cv_{calorimeter}\Delta T$

Thus, given the released heat by the hamburger due to its combustion and the temperature change, Cv for the calorimeter turns out:

$Cv_{calorimeter}=\frac{-Q_{hamburguer}}{\Delta T} =\frac{-(-335.4kcal)}{18.2K}\\\\Cv_{calorimeter}=18.4kcal/K$

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