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3 years ago

The passage below describes an experiment. Read the passage and then follow the instructions below.

Chemistry

1 answer:

leva [86]3 years ago

8 0

Answer:

25 - (8 1/3 + 3)

Explanation:

This is the equation to the answer. 8 1/3 seeds were potted in 3 of the 6 pots. so now Gabby has 16 2/3 seeds.

hope this helps.

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What is the concentration in g/L of a solution containing 10 g of solute in 2 L of solution

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The concentration is 5 g/L.

Concentration = mass/volume = 10 g/2 L = 5 g/L

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Substances that are likely to disassociate in water

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Answer:

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Atomic size of inert gases do not affect you inertness why

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2 years ago

Are scientific theories all proven facts?

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3 years ago

Read 2 more answers

Phosgene (COCl2) is a toxic substance that forms readily from carbon monoxide and chlorine at elevated temperatures: CO(g) + Cl2

lapo4ka [179]

Answer: Concentration of $CO$ = 0.328 M

Concentration of $Cl_2$ = 0.328 M

Concentration of $COCl_2$ = 0.532 M

Explanation:

Moles of $CO$ and $Cl_2$ = 0.430 mole

Volume of solution = 0.500 L

Initial concentration of $CO$ and $Cl_2$ = $\frac{moles}{volume}=\frac{0.430}{0.500}=0.860M$

The given balanced equilibrium reaction is,

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial conc. 0.860M 0.860M 0

At eqm. conc. (0.860-x) M (0.860-x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[COCl_2]}{[CO][Cl_2]}$

Now put all the given values in this expression, we get :

$4.95=\frac{x}{(0.860-x)^2}$

By solving the term 'x', we get :

x = 0.532 M

Thus, the concentrations of $CO,Cl_2\text{ and }COCl_2$ at equilibrium are :

Concentration of $CO$ = (0.860-x) M =(0.860-0.532) M = 0.328 M

Concentration of $Cl_2$ = (0.860-x) M = (0.860-0.532) M = 0.328 M

Concentration of $COCl_2$ = x M = 0.532 M

3 0

3 years ago