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FromTheMoon [43]
3 years ago
6

Which of the following statements is not true regarding acids?

Chemistry
2 answers:
NikAS [45]3 years ago
8 0
Active metals will react with acids in double replacement reactions. 

<span>NH4+ </span>

<span>increase the volume </span>
<span>add a catalyst</span>
aev [14]3 years ago
6 0
The correct answer is the last option. Active metals will not react with acids in double replacement reactions. Instead, it reacts with metals via sing replacement reactions. It will displace hydrogen from the acid.
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Mike, Jackie, Jeremy, and Niki were widely known to the be the fastest fifth graders at Robinson Elementary School. They wanted
riadik2000 [5.3K]

Jackie is the fastest student. (Option A)

Explanation:

  • From the table it was understood that their speeds are given in meter per second, that is how many meters they run in one second. It was again shown that Jackie's race speed is 5.3 meter per second and all the other three namely Jeremy's speed is 3.9 meter per second, Mike's speed is 4.1 meter per second and finally Niki's speed is 3.8 meter per second.
  • So, by comparing with others Jackie is the fastest runner in that race.
8 0
3 years ago
Classify each element as a metal, nonmetal, or semimetal. br in cr ca drag the appropriate items to their respective bins. view
goldenfox [79]
Below is the distribution of given elements and additional elements in their respective bins.

Iron, Magnesium, Aluminium, Calcium, Chromium and Indium are classified as Metals due to their hardness, conduction of current and heat, Solid state, formation of metallic bonding and prefers to form cations e.t.c

Oxygen, Neon and Bromine are classified as non-metals. Non-metals are mostly gases except for Bromine. They are highly volatile and prefers to form anions.

Semimetals are those metals which have both properties of metals and non-metals and are also called as metalloids.

6 0
3 years ago
A scientist is conducting an experiment with sand. Some iron filings accidentally fell into the sand. What could the scientist u
anzhelika [568]
Get a magnet in a bag (inside out) and move the magnet all over the sand/iron and you can collect all the iron and turn the bag right side out and zip up the bag. Now you have the sand and iron separated and it will be harder to accidentally mix them later.
7 0
3 years ago
Read 2 more answers
Lead(II) nitrate is added slowly to a solution that is 0.0800 M in Cl− ions. Calculate the concentration of Pb2+ ions (in mol /
barxatty [35]

Answer:

[Pb^{2+}]=3.9 \times 10^{-2}M

this is the concentration required to initiate precipitation

Explanation:

PbCl_2  ⇄ Pb^{2+}+2Cl^-

Precipitation starts when ionic product is greater than solubility product.

Ip>Ksp

Precipitation starts only when solution is supersaturated because solution become supersaturated then it does not stay in this form and precipitation starts itself only solution become saturated.

This usually happens when two solutions containing separate sources of cation and anion are mixed together and here also we are mixing lead (||)nitrate solution(source of lead(||)) into the Cl- solution.

Ip=[Pb^{2}][2Cl^-]^2=Ksp

Ksp=2.4\times 10^{-4}

lets solubility=S

[Pb^{2+}] = S

[Cl^-]=2S

Ksp=[Pb^{2+}]\times [Cl^-]^2

Ksp=S \times (2S)^2

Ksp=4S^3

S=\sqrt[3]{\frac{Ksp}{4} }

S=3.9\times 10^{-2}

[Pb^{2+}]=3.9 \times 10^{-2}M this is the concentration required to initiate precipitation

4 0
3 years ago
7.02 x 10^23 molecules of X2, a ssubstance consisting of diatomic molecules, has a mass of 296 grams. Determine the atomic weigh
Fiesta28 [93]

Answer:

d. 127 g/mol.

Explanation:

Hello!

In this case, since we have the amount of molecules of this this compound, we are able to compute the moles out there by using the Avogadro's number:

mol=7.02x10^{23}molec*\frac{1mol}{6.022x10^{23}molec}=1.17mol

Which correspond to the moles of X2. Then, by using the mass we are able to compute the molar mass of X2:

MM=\frac{296g}{1.17mol}\\\\MM=254g/mol

It means that the atomic mass of X halves the molar mass of X2, which is then d. 127 g/mol.

Best regards!

4 0
3 years ago
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