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melisa1 [442]
3 years ago
6

Which sample contains the same number of atoms as 24 grams of

Chemistry
1 answer:
Drupady [299]3 years ago
6 0

Answer:

24 g Mg

Explanation:

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1) Chemistry is a (physical/biological) science?
den301095 [7]

Answer:

Explanation:

Biological.

I hope I helped you! :)

4 0
3 years ago
When 42.5 g of benzamide (C7H7NO) are dissolved in 500 g of a certain mystery liquid X, the freezing point of the solution is 6.
LuckyWell [14K]

Answer:

21.3g of Fe(NO₃)₃ are required to produce the same depression in freezing point of solution.

Explanation:

Freezing point depression is a colligative property which indicates, in determined mixture, the freezing point of solution is lower that the freezing point of the solvent, according the amount of solute.

Formula is: ΔT = Kf . m . i

Kf is the cryoscopic constant, which is particular for each solvent. We do not have that data, so we need to find it out in order to solve the question:

ΔT = Freezing point of pure solvent - Freezing point of solution.

This data is known → 6.40°C

m, means molality, moles of solute in 1kg of solvent. Let's get the moles of benzamide: 42.5 g . 1mol / 121g = 0.351 moles

m = 0.351 mol / 0.5kg = 0.702 m

As benzamide is an organic compound i, = 1. i are the number of ions dissolved in solution. Let's find out Kf:

6.40°C = Kf . 0.702 m . 1

6.40°C /0.702m = 9.11 °C/m.

Let's go to the next question.

ΔT is the same → 6.40°C

But this is, an inorganic salt, a ionic salt: Fe(NO₃)₃ →  1Fe³⁺  + 3NO₃⁻

For this case, we have 1 mol of Iron(III) and 3 nitrates, so i = 4

Let's replace data: 6.40°C = 9.11 °C/m . m . 4

6.40°C / (9.11 m/°C . 4) = 0.176 m

This data represents that, in 1 kg of solvent we have 0.176 moles of nitrate.

Mass of solvent X required in this case is 0.500 kg, so, the moles that are contained are: 0.500 kg . 0.176 mol/kg = 0.088 mol

Let's determine the mass of salt: 0.088 mol . 241.85g /1mol = 21.3 g

5 0
3 years ago
Why is a kite flying in the sky an example of potential energy?
Alenkinab [10]
The answer is b because the wind exerts a force on the kite
6 0
4 years ago
Consider the following balanced equation:
kow [346]

Answer:

The theoretical yield of Cu(s) in moles is 60.15 moles

Explanation:

Step 1: Data given

Number of moles CuO = 70.8 moles

Number of moles NH3 = 40.1 moles

Molar mass CuO = 79.545 g/mol

Molar mass NH3 = 17.03 g/mol

Step 2: The balanced equation

3CuO(s) + 2NH3(g) → 3H2O(l) + 3Cu(s) + N2(g)

For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2

NH3 is the limiting reactant. It will completely be consumed (40.1 moles). CuO is in excess. There will react 3/2 * 40.1 = 60.15 moles

There will remain 70.8 - 60.15 = 10.65 moles CuO

Step 3: Calculate moles Cu

For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2

For 40.1 moles NH3 we'll have 60.15 moles Cu

The theoretical yield of Cu(s) in moles is 60.15 moles

8 0
4 years ago
How many moles of aluminum oxide (Al2O3) are in a sample with a mass of 204. 0 g? 1. 000 2. 000 3. 0.
Aleks [24]

Answer:

<u>1</u><u>.</u><u> </u><u>0</u><u>0</u><u>0</u><u>.</u><u>2</u>

Explanation:

<u> </u><u> </u><u>a</u><u>l</u><u>u</u><u>m</u><u>i</u><u>n</u><u>u</u><u>m</u><u> </u><u>o</u><u>x</u><u>i</u><u>d</u><u>e</u><u> </u><u>m</u><u>a</u><u>d</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>m</u><u>o</u><u>l</u><u>e</u><u>s</u><u> </u><u>o</u><u>r</u><u> </u><u>a</u><u>t</u><u>o</u><u>m</u><u>s</u><u> </u><u>l</u><u>e</u><u>s</u><u>s</u><u> </u><u>t</u><u>h</u><u>e</u><u>n</u><u> </u><u>o</u><u>t</u><u>h</u><u>e</u><u>r</u><u> </u><u>e</u><u>l</u><u>e</u><u>m</u><u>e</u><u>n</u><u>t</u><u>s</u><u> </u><u>n</u><u>e</u><u>e</u><u>d</u><u> </u><u>t</u><u>o</u><u> </u><u>d</u><u>e</u><u>c</u><u>r</u><u>e</u><u>a</u><u>s</u><u>e</u>

6 0
3 years ago
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