Answer:
see explanation
Step-by-step explanation:
Given
-
[ -
c + 6c + 1 ] - 3c
Distribute the square bracket by - 
=
c - 3c -
- 3c ← combine like terms
=
c - 6c - 
=
c -
c - 
= -
c - 
![\left( \dfrac 1 {64} \right)^{- 5/6} =64^{5/6} = (\sqrt[6]{64})^5 = 2^5 =32](https://tex.z-dn.net/?f=%20%5Cleft%28%20%5Cdfrac%201%20%7B64%7D%20%5Cright%29%5E%7B-%205%2F6%7D%20%3D64%5E%7B5%2F6%7D%20%3D%20%28%5Csqrt%5B6%5D%7B64%7D%29%5E5%20%3D%202%5E5%20%3D32)
TRUE
![\sqrt[5]{36^4}=36^{4/5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B36%5E4%7D%3D36%5E%7B4%2F5%7D)
which surely isn't 36. FALSE

FALSE
For the fourth one we have a

which isnt

so this is FALSE.





No fractions in that one so FALSE.
Answer:a+b
Step-by-step explanation:
You can use the variables a and b to solve your equation if you need
Answer:
yes, brother can go
Step-by-step explanation:
Apparently, you're not to think to deeply about this function. Rather, you are to take the question at face value. It is asking if the value of T(3) is more than 58.
Evaluation of polynomials is facilitated by writing them in "Horner form."
T(x) = ((x -2)x +1)x^2 +27
T(3) = ((3 -2)3 +1)9 +27 = (3 +1)9 +27 = 36 +27
T(3) = 63
The coldest temperature is supposed to be 63 degrees, which is above 58 degrees. Baby brother can come along.