We have three numbers to arrange so that 6 is 1/10 of the value of the other six.
Since position tells us whether we're talking about single, tens, hundreds, thousands (e.g. 25 is two times 10 plus five times 1) we know that the two sixes must be next to each other.
This leaves us with two options.
663 or 366.
In each of these cases the second 6 in the number is one tenth of the first 6.
If we look at the only other option: 636 we see that the second 6 is one hundredth of the value of the first 6.
Answer:
32
Step-by-step explanation:
The formula needed to solve this question by hand is:
![x^{\frac{m}{n}} =\sqrt[n]{x^{m}}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%20%3D%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%7D)
256^(5/8) = 8th root of 256^5
256^(5/8) = 8th root of 1280
<u>256^(5/8) = 32</u>
Answer:
I think it's 2566.8 if 4.6 is taken out of the account annually. I think that is what it is asking.. I'm only 13 so I'm not great at these yet but it should be right because I'm really good at math
Step-by-step explanation:
Answer: 
Step-by-step explanation:
<u>Given information</u>
Point B = (-2, -4)
Reflection line: y = x
<u>Concept:</u>
When reflecting over the line y = x, the position of y and x in the original coordinate switches places.
This is because it is " y = x ", assuming that they could interchange
<u>Find the coordinate of Point B'</u>
Original (x, y) = (-2, -4)
Point B' = (x', y') = (y, x) = 
<em>Please refer to the attachment below for a graphical understanding</em>
Hope this helps!! :)
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