Find the distance between (0,6) and (-6,0).

Please help me please I need help!!!!!!!!!!!!!!!!!!!hshdjdndndbdbnfjfkfkfkdkdkfkfjdjfiid

Serggg [28]

y = (x - 2)(x + 5) First I would multiply (x - 2) and (x + 5) together

y = x² + 5x - 2x - 10

y = x² + 3x - 10

Next I would plug in a number for x to find its y value. I will plug in 0

y = 0² + 3(0) - 10

y = -10

(0, -10) [this is the y-intercept (the y value when x = 0)]

Your answer is Graph A because the y-intercept is (0,-10)

6 0

3 years ago

A building casts a shadow 168 meters long. At the same time, a pole 5 meters high casts a shadow 20 meters long . What is the he

yawa3891 [41]

Answer:

42

Step-by-step explanation:

The height of the pole is 4 times shorter than the length of the shadow 20÷5=4

The height of the building must be 4 times shorter than its shadow length 168÷4=42

3 0

3 years ago

(08.07 HC)

andreev551 [17]

Answer:

$\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}$

$\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)$

C) See attachment.

Step-by-step explanation:

Given function:

$f(x)=2x^2-x-10$

To factor a <u>quadratic</u> in the form $ax^2+bx+c$ <em> , </em>find two numbers that multiply to $ac$ and sum to $b$ :

$\implies ac=2 \cdot -10=-20$

$\implies b=-1$

Therefore, the two numbers are -5 and 4.

Rewrite $b$ as the sum of these two numbers:

$\implies f(x)=2x^2-5x+4x-10$

Factor the first two terms and the last two terms separately:

$\implies f(x)=x(2x-5)+2(2x-5)$

Factor out the common term (2x - 5):

$\implies f(x)=(x+2)(2x-5)$

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

$\implies (x+2)(2x-5)=0$

Therefore:

$\implies (x+2)=0 \implies x=-2$

$\implies (2x-5)=0 \implies x=\dfrac{5}{2}$

So the x-intercepts are:

$x=-2, \:\:x=\dfrac{5}{2}$

The x-value of the vertex is:

$\implies x=\dfrac{-b}{2a}$

Therefore, the x-value of the vertex of the given function is:

$\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}$

To find the y-value of the vertex, substitute the found value of x into the function:

$\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}$

Therefore, the vertex of the function is:

$\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)$

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards. This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>. Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

5 0

2 years ago

Can anyone fill these out?

Tcecarenko [31]

Answer:

Part (a)

36

Part (b)

Find the filled table in the attachment

Part (c)

1/36

Step-by-step explanation:

The total number of possible outcomes using the multiplicative rule is given by;

6*6 = 36.

There are 6 possible outcomes in rolling each die, we simply find the product.

The probability of rolling double sixes is given by;

pr(6 and 6) = pr(6) * pr(6) = 1/6 * 1/6 = 1/36

The probability of rolling double sixes represents independent events and thus we employ the multiplicative rule of probability.

8 0

3 years ago

A number subtracted from 16 is -3

rusak2 [61]

Simplify it to 16a hope im right & hope this helps you .

7 0

3 years ago

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