Answer:
When the pressure increases to 90.0 atm , the volume of the sample is 0.01467L
Explanation:
To answer the question, we note that
P₁ = 1.00 atm
V₁ = 1.32 L
P₂ = 90 atm.
According to Boyle's law, at constant temperature, the volume of gas is inversely proportional to its pressure
That is P₁V₁ = P₂V₂
Solving the above equation for V₂ we have
that is V₂ =
=
or 0.01467L
The equilibrium constant k is actually the ratio of the
concentration of the products over the concentration of reactants at equilibrium. So if the
concentration of products < concentration of reactants, therefore the
constant k will be small. But if the concentration of products >
concentration of reactants, the constant k will be large. In this case the
value is too small (x10^-19), therefore we can say that the reaction favors the
reactant side:
the equilibrium lies far to the left
According to Law of conservation of matter," matter can neither be created nor destroyed but is conserved and remains constant over time'.
In above picture let suppose the Blue balls represent N₂ molecule and White balls represent H₂ molecules.
So, left picture represent reactants,
2 N₂ + 6 H₂
And , right picture represent products,
4 NH₃
So, there are 4 N atoms and 12 Hydrogen atoms in reactants and 4 N atom and 12 Hydrogen atoms in products. Means the mass of elements is conserved. The overall reactions is as follow,
2 N₂ + 6 H₂ → 4 NH₃
Result:
Yes! This reaction follow Law of conservation of Matter.
Henry law:
P = KC
P = solvent vapour pressure
K = Henry constant
C = conc of solute
So, 0.2 = 773 C
so, C = 0.2 / 773 = 2.5 x 10^{-4} molal
Answer:
The water absorbs the thermal energy of the fire.
Explanation:
Thermal energy a form of energy that is produced when a rise in temperature causes atoms and molecules to move faster and collide with each other. It is a form of energy which involves the transfer of energy from regions of higher heat content to regions of lower heat content.
A burning wood fire has a higher heat content than water. Therefore, when water is thrown on a wood fire, the water will absorb the heat from the burning wood fire in order to raise its own heat content. since the wood fire has lost heat to water, it would eventually stop burning, whereas the water whose heat content has been raised may have some of its molecules absorbing so much heat that a change of phase occurs to the liquid phase.