D. <span>carbon and hydrogen</span>
Answer:
D. ![K_{a} = \frac{[\text{H}^{+}][\text{NO}_{2}^{-}]}{[\text{HNO}_{2}]}](https://tex.z-dn.net/?f=K_%7Ba%7D%20%3D%20%5Cfrac%7B%5B%5Ctext%7BH%7D%5E%7B%2B%7D%5D%5B%5Ctext%7BNO%7D_%7B2%7D%5E%7B-%7D%5D%7D%7B%5B%5Ctext%7BHNO%7D_%7B2%7D%5D%7D)
Explanation:
The general form of an equilibrium constant expression is
![K = \frac{[\text{Products}]}{[\text{Reactants}]}](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5B%5Ctext%7BProducts%7D%5D%7D%7B%5B%5Ctext%7BReactants%7D%5D%7D)
In the equilibrium
HNO₂ ⇌ H⁺ + NO₂⁻
The products are H⁺ and NO₂⁻, and the reactant is HNO₂.
∴
Answer:
The bond order for C2 molecule is 2.
Explanation:
Bond order can be defined as the half of the difference between the number of electrons in the bonding orbital and the number of electrons in the antibonding orbitals. It can be represented mathematically by; .
Bond order,n= [number of electrons in the bonding molecular orbitals(BMO) - the number or electrons in the anti-bonding molecular orbitals(AMO) ] / 2.
The electronic configuration of the C2 molecule is given below;
C2 = (1sσ)^2 (1s^*σ)^2 (2sσ)^2 (2s^*σ)^2 (2pπ)^4.
The ones with the (*) are known as the Anti-bonding molecular orbitals while the ones without (*) are known as the bonding molecular orbitals. Hence, we have 8 Electrons from the bonding molecular orbitals and 4 Electrons from the anti-bonding molecular orbitals.
So, from the formula given above, the bond order of C2 molecule is;
===> 8-4/2= 4/2.
===> 2.
increase the rate of chemical change.
Explanation:
The reaction of the metal oxide with water to form a base in the presence of a spike in temperature will lead to an increase in the rate of chemical change.
Temperature change has considerable effect on reaction rates.
- Temperature is directly proportional to the average kinetic energy of reacting particles.
- Reaction rates varies directly with a spike in temperature.
- It has been known that for every 10°C rise in temperature, above the room temperature, reaction rates become double or tripled.
- Temperature increases the kinetic energy of each of the reacting particles.
- Many of the reacting particles also acquires an energy greater than or equal to the activation energy of the reaction.
- The frequency of ordinary collisions and effective collisions per unit time increases.
Learn more;
Activation energy brainly.com/question/3930233
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