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Andreas93 [3]
3 years ago
14

Can anyone help with chem please.

Chemistry
1 answer:
Schach [20]3 years ago
4 0

B. Bent or v shaped

this is my answer

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Find the density of Liquid A: Liquid A: Mass-138g Volume – 100 mL.
nlexa [21]

Answer:

The answer is

<h2>1.38 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass of liquid = 138 g

volume = 100 mL

The density of the liquid is

density =  \frac{138}{100}  = \frac{69}{5 0}

We have the final answer as

<h3>1.38 g/mL</h3>

Hope this helps you

7 0
3 years ago
Iron is ___<br> A, FE<br> B,CU<br> C,K<br> D, CA
Fiesta28 [93]

<em>Answer:</em>

<em>Ello mate ! the answer is super simple it's option "A" Fe</em>

<em>Explanation:</em>

<em>Iron is a chemical element with symbol</em><em> "Fe"</em><em> and atomic number 26. It is a type of metal, that belongs to the first transition series and group 8 of the periodic table. It is by mass the most common element on Earth, forming much of Earth's outer and inner core.</em>

5 0
4 years ago
Read 2 more answers
What is the mass number of an atom with 17 protons, 17 electrons, and 20 neutrons?
astra-53 [7]
The mass number of this particular element is 37

An element with 17 protons will ALWAYS be chlorine.
The mass number is found by adding the element’s protons and neutrons.
protons+neutrons=mass number

Here is the math if needed,
17+20=37

Therefore the mass number is 37

I hope this helped!
3 0
4 years ago
A galvanic cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). W
Agata [3.3K]

Answer : The 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Explanation :

Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the voltaic cell or electrochemical cell.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

We are taking the value of standard reduction potential form the standard table.

E^0_{[Ag^{+}/Ag]}=+0.80V

E^0_{[Cu^{2+}/Cu]}=+0.34V

In this cell, the component that has lower standard reduction potential gets oxidized and that is added to the anode electrode. The second forms the cathode electrode.

The balanced two-half reactions will be,

Oxidation half reaction (Anode) : Cu(s)\rightarrow Cu^{2+}(aq)+2e^-

Reduction half reaction (Cathode) : Ag^{+}(aq)+e^-\rightarrow Ag(s)

Thus the overall reaction will be,

Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

From this we conclude that, 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Hence, the 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

7 0
3 years ago
You have studied the gas-phase oxidation of HBr by O2: 4 HBr(g) + O2(g) → 2 H2O(g) + 2 Br2(g) You find the reaction to be first
Vlada [557]

Answer:

Explanation:

FIND THE SOLUTION IN THE ATTACHMENT

4 0
3 years ago
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