Answer:
c. AgNO₃(aq) + NH₄Cl(aq) ->AgCl(s) + NH₄NO₃(aq)
Explanation:
We have to follow the <u>solubility rules</u> to check the states of each compound.
-) All the cholride salts are soluble EXCEPT those also containing: lead, silver or mercury.
-) All the nitrate and ammonium salts
are soluble.
With this in mind ,
and
would be soluble, so we have to use the <u>aqueosus state (aq).</u>
The then would have a <u>solid state (s)</u>.
Answer:
168 g
Reaction:
Explanation:
First we need to figure out what is the formula mass (Mr) of Fe2O3 (Iron(III) oxide).
The atomic mass of Fe=56, O=16
Mr= 56+56+16+16+16=160 g/mol
We can now figure out the moles of the iron:
240/160 = 1.5 mol
Then we need to find the ratio to make Fe.
In the reaction, we know that 1 mole of Fe2O3 can make 2 moles of Fe. So 1.5 moles of Fe2O3 can make 3 moles of Fe.
And then we need to find the mass of the Fe.
3×56=168 g.
Hence 168g of the iron is made after the reaction.