13.5g H2O = 13.5/(2+16) = 0.75 mol H2O
Since for every O2 you can form 2 H2O, 0.75/2 = 0.375 mol of O2 will be needed to form 0.75 mol of H2O.
Converting from moles to molecules:
0.375 mol * 6.022 * 10^23 = 2.26 * 10 ^23 molecules
Answer:
9.39 × 10²² molecules
Explanation:
We can find the moles of gases (n) using the ideal gas equation.
P . V = n . R . T
where,
P is the pressure (standard pressure = 1 atm)
V is the volume
R is the ideal gas constant
T is the absolute temperature (standard temperature = 273.15 K)
There are 6.02 × 10²³ molecules in 1 mol (Avogadro's number). Then,
Answer:
0.574moles
Explanation:
Using the general gas equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (Litres)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (Kelvin)
According to the information provided in the question;
- Volume (V) = 12400mL = 12400/1000 = 12.4L
- Pressure (P) = 890mmHg = 890/760 = 1.17atm
- Temperature (T) = 35°C = 35 + 273 = 308K
Hence, using PV = nRT
n = PV/RT
n = 1.17 × 12.4 ÷ 0.0821 × 308
n = 14.508 ÷ 25.287
n = 0.574moles
Therefore, the number of moles of argon gas in the cylinder is 0.574moles
Non of the above because protons and neutrons don’t mix with each one there
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