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bearhunter [10]
3 years ago
12

. Starting from a stop at a traffic signal, a car speeds up to 20 m/s in 5 seconds. Calculate the acceleration of the car.

Physics
1 answer:
Dimas [21]3 years ago
4 0

Answer: 4m/s²

Explanation:

At stop signal car speed iz 0 ; V1=0m/s

After t=5s  , car has speed is V2=20m/s

using:

a=(V2-V1)/t

a=(20m/s-0m/s)/5s

a=20m/s/5s

a=4m/s²

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Two stones resembling diamonds are suspected of being fakes. To determine if the stones might be real, the mass and volume of ea
dimaraw [331]

Answer:

stone A is diamond.

Explanation:

given,

Volume of the two stone =  0.15 cm³

Mass of stone A = 0.52 g

Mass of stone B = 0.42 g

Density of the diamond =  3.5 g/cm³

So, to find which stone is gold we have to calculate the density of both the stone.

We know,

density\density = \dfrac{mass}{volume}

density of stone A

\rho_A = \dfrac{0.52}{0.15}

\rho_A = 3.467\ g/cm^3

density of stone B.

\rho_B = \dfrac{0.42}{0.15}

\rho_B = 2.8\ g/cm^3

Hence, the density of the stone A is the equal to Diamond then stone A is diamond.

6 0
3 years ago
A boy threw a ball upward and it took 3 sec to reach the highest point. Determine the initial velocity of the ball.
makkiz [27]

Answer:

V initial = 29.4 m.s²

Explanation:

( Using the laws of motion)

V final = V initial + Acceleration × time

0 = V initial + ( -9.8)(3)

29.4 = V initial

* I took upward as positive that's why I substituted -9.8 *

* for V final we know that at maximum height the ball is not moving thats why is = 0 *

6 0
2 years ago
bromine, chlorine, and fluorine are examples of A. halogens B. Metalloids C. Noble Gases or D. Alkali metals
Bumek [7]

A) halogens.

bromine, chlorine and fluorine are found in group 7 of the periodic table. thus they are halogens

4 0
3 years ago
Read 2 more answers
Why do we need landforms
Vera_Pavlovna [14]
To understand processes responsible for formation of different landforms in the past as well as present. To have scientific landuse for present and future. 
5 0
3 years ago
Read 2 more answers
provides one model for solving this problem. The maximum strength of the earth's magnetic field is about 6.9 x 10-5 T near the s
jeka57 [31]

Answer:

The minimum no. of turns is 3.126 \times 10^{5}

Explanation:

Given:

Magnetic field B = 6.9 \times 10^{-5} T

Frequency f = 84.5 Hz

Area of turn A = 0.021 m^{2}

Voltage V_{rms}  = 170 V

From the formula of induced emf,

V = NBA \omega

Where \omega = 2\pi f and V = \sqrt{2} V_{rms}

So number of turn is,

N = \frac{\sqrt{2} V_{rms} }{AB2\pi f }

N = \frac{\sqrt{2} \times 170 }{0.021 \times 6.9 \times 10^{-5} \times 6.28 \times 84.5 }

N = 3.126 \times 10^{5}

Therefore, the minimum no. of turns is 3.126 \times 10^{5}

4 0
3 years ago
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