Answer:
A) affinity pattern
Explanation:
Affinity patterns show associations that occur among objects in the real world. These objects that show affinity patterns or association patterns are not complementary to each other and sometimes may not even be related to each other.
In this case, the fact that it is raining is probably what causes the 85% in cab service usage. If we analyze them separately, cab service and rain have nothing to do with each other, but when it rains more cabs are used.
Answer:
the issue price of the bonds is $593,177
Explanation:
The computation of the issue price of the bonds is shown below:
Particulars Amount PV factorat 5% Present value
Semi-annual interest $28,350 11.68959 $331,400
Principal $630,000 0.41552 $261,778
Total $593,177
hence, the issue price of the bonds is $593,177
Answer:
<u>The correct answer is that Rachel's workshop total cost is US$ 5,700 per month and US$ 19 of average cost per unit sold every month.</u>
Explanation:
<u>1. Rachel's workshop monthly costs</u>
Rent US$ 600
Salaries US$ 3,600
Insurance premium US$ 300
Raw materials US$ 1,200
<u>Total monthly costs US$ 5,700</u>
<u>2. Rachel's workshop average monthly costs</u>
Number of units sold per month = 300
Average monthly costs = Total monthly costs/Number of units sold
Average monthly costs = 5,700/300
<u>Average monthly costs = US$ 19</u>
Answer:
Keyboard helps a user to type a letter,number and etc..
Answer:
Explanation:
Data given and notation
represent the sample mean
represent the standard deviation for the sample
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to determine if the mean is lower than 5600, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this: