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4 years ago

What is the mass of an aluminum cylinder with 0.234 in diameter and a length of 2.697

Chemistry

1 answer:

Lemur [1.5K]4 years ago

8 0

0.33g

Explanation:

Given parameters:

Diameter of cylinder = 0.234cm

length = 2.697cm

unknown:

mass of the cylinder = ?

Solution:

To solve this problem, we know that density of the aluminium can be determined and it is a constant.

Density is the mass per unit volume of a substance

Density = $\frac{mass}{volume}$

Mass of the cylinder = density x volume

To calculate the volume of cylinder;

Volume = π r² h

radius of the cylinder = $\frac{0.234}{2}$ = 0.12cm

Volume = 3.142 x 0.12² x 2.697 = 0.12cm³

Density of aluminium = 2.7g/cm³

Mass of the cylinder = 0.12 x 2.7 = 0.33g

learn more:

Density brainly.com/question/2690299

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Answer: The empirical formula is $H_2S_2O_3$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

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Mass of S = 56.1 g

Mass of O = 42.1 g

Step 1 : convert given masses into moles.

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.8g}{1g/mole}=1.8moles$

Mass of S = $\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{56.1g}{32g/mole}=1.8moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{42.1g}{16g/mole}=2.6moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For H = $\frac{1.8}{1.8}=1$

For S = $\frac{1.8}{1.8}=1$

For O = $\frac{2.6}{1.8}=1.5$

Converting to whole number ratios

The ratio of H: S: O= 2: 2: 3

Hence the empirical formula is $H_2S_2O_3$

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3 years ago

What volume of 0.200 M ethanol solution contains each of the following amounts?

Papessa [141]

Answer:

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B. 6.10 L

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Explanation:

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In this case:

0.200 M = moles of ethanol / Liters of solution

So from the formula we can get that we can calculate the volume of the solution, as Liters of solution, given the moles in each case as:

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_______________________________________________

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Liters of solution = 1.22 moles / 0.200 moles/L = 6.10 L

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Note: Each answer is given with the correct number of significant figures which results from the least number of significant figures in the given used values in each calculation.

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