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Crank
3 years ago
12

What is the mass of an aluminum cylinder with 0.234 in diameter and a length of 2.697

Chemistry
1 answer:
Lemur [1.5K]3 years ago
8 0

0.33g

Explanation:

Given parameters:

Diameter of cylinder = 0.234cm

length = 2.697cm

unknown:

mass of the cylinder = ?

Solution:

To solve this problem, we know that density of the aluminium can be determined and it is a constant.

 Density is the mass per unit volume of a substance

 Density = \frac{mass}{volume}

 Mass of the cylinder = density x volume

To calculate the volume of cylinder;

  Volume = π r² h

     radius of the cylinder = \frac{0.234}{2} = 0.12cm

Volume = 3.142 x 0.12² x 2.697 = 0.12cm³

Density of aluminium = 2.7g/cm³

 Mass of the cylinder = 0.12 x 2.7 = 0.33g

learn more:

Density brainly.com/question/2690299

#learnwithBrainly

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Answer:

If I could have a super power it would be invisibility. Sometimes you wish you weren't there and if you were hiding from someone then they couldn't find you.

3 0
2 years ago
Is it possible for the equivalence point of a titration to not be at pH 7? Explain your answer.
lara31 [8.8K]
<span>The reason it will be 7 for some titrations is that when you  titrates a strong acid with a strong base for example  HCl and NaOH the salt formed is conjugate base of strong acid and will be a very weak base
 That means that it cannot produce any OH^-1 and all the H+ has been converted to water.The only source of H+ or OH is water with a Ka of 10^-14 so the pH = -log [H+]=-log 10^-7 = 7 
second reason is 
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only a water solution of the conjugate base exists 

CH3COOH + NaOH ----- Na+ CH3COO^-1 + H2O 
Since the conjugate base is the conjugate base of a weak acid it will hydrolyze in water like so 
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hope this helps</span>
5 0
3 years ago
Read 2 more answers
HIII PLEASE HELP BRUUH
leonid [27]

1. 2Al(s)+6HCl(aq)⇒2AlCl₃(aq)+3H₂(g)

2. 2AgNO₃ (aq) + Cu (s)⇒Cu(NO₃)₂ (aq) + 2Ag (s)

3. 2C₃H₈O(l) + 9O₂(g) ⇒ 6CO₂(g) + 8H₂O(g)

<h3>Further explanation</h3>

There are several reactions that can occur in a chemical reaction: single replacement, double replacement, synthesis, decomposition or combustion, etc.

1.Al(s)+HCl(aq)⇒AlCl₃(aq)+H₂(g)

type : single replacement

balance :

2Al(s)+6HCl(aq)⇒2AlCl₃(aq)+3H₂(g)

2. AgNO₃ (aq) + Cu (s) ⇒ Cu(NO₃)₂ (aq) + Ag (s)

type : single replacement

balance :

2AgNO₃ (aq) + Cu (s)⇒Cu(NO₃)₂ (aq) + 2Ag (s)

3. C₃H₈O + O₂ ⇒ CO₂ + H₂O

type : combustion of alcohol

balance :

2C₃H₈O(l) + 9O₂(g) ⇒ 6CO₂(g) + 8H₂O(g)

4 0
2 years ago
What is the mass of 5.84 × 10^21 atoms of xenon?
podryga [215]

Answer:

5.84e+21

Explanation:

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2 years ago
Calculate the molarity of 0.289 moles of FeC13 dissolved in 120 ml of solution
yanalaym [24]

Answer:

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Explanation:

The molarity is the moles of FeCl3 over the liters of solution. Since you're given mL you need to change it to L which is 0.12 L. 0.289 divided by 0.12 is your answer

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3 years ago
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