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Crank
3 years ago
12

What is the mass of an aluminum cylinder with 0.234 in diameter and a length of 2.697

Chemistry
1 answer:
Lemur [1.5K]3 years ago
8 0

0.33g

Explanation:

Given parameters:

Diameter of cylinder = 0.234cm

length = 2.697cm

unknown:

mass of the cylinder = ?

Solution:

To solve this problem, we know that density of the aluminium can be determined and it is a constant.

 Density is the mass per unit volume of a substance

 Density = \frac{mass}{volume}

 Mass of the cylinder = density x volume

To calculate the volume of cylinder;

  Volume = π r² h

     radius of the cylinder = \frac{0.234}{2} = 0.12cm

Volume = 3.142 x 0.12² x 2.697 = 0.12cm³

Density of aluminium = 2.7g/cm³

 Mass of the cylinder = 0.12 x 2.7 = 0.33g

learn more:

Density brainly.com/question/2690299

#learnwithBrainly

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Pls help Would be much appreciated:)
Pie

Answer:

Ok so,  b. A redox reaction occurs in an electrochemical cell, where silver (Ag) is oxidized and nickel (Ni) is reduced - In voltaic cells, also called galvanic cells, oxidation occurs at the anode and reduction occurs at the cathode. A mnemonic for this is "An Ox. Red Cat." So since silver is oxidized, the silver half-cell is the anode. And the nickel half-cell is the cathode...

i. Write the half-reactions for this reaction, indicating the oxidation half-reaction and the reduction half-reaction- The substance having highest positive  potential will always get reduced and will undergo reduction reaction. Here, zinc will always undergo reduction reaction will get reduced

ii. Which metal is the anode, and which is the cathode?-The anode is where the oxidation reaction takes place. In other words, this is where the metal loses electrons. The cathode is where the reduction reaction takes place.

iii. Calculate the standard potential (voltage) of the cell

Look up the reduction potential,

E

⁰

red

, for the reduction half-reaction in a table of reduction potentials

Look up the reduction potential for the reverse of the oxidation half-reaction and reverse the sign to obtain the oxidation potential. For the oxidation half-reaction,

E

⁰

ox

=

-

E

⁰

red

.

iv. What kind of electrochemical cell is this? Explain your answer.

All parts in the electrochemical cells are labeled in second figure. Following are the part in electrochemical cells

1) Anode 2) Cathode 3) gold Stripe (Electrode) 4) Aluminium Glasses (Electrode) 5) Connecting wires 6) Battery

Explanation:

3 0
3 years ago
Which of the following is the smallest volume?
jok3333 [9.3K]
The     (B) answer     (B)     is    (B)               (B)           (B)


6 0
3 years ago
PLEASE ANSWER ASAP I WILL GIVE BRAINLIEST!!
anzhelika [568]
It’s lower, hope this helps with your issue and helps solve your problem, no problem
5 0
3 years ago
Read 2 more answers
Which of the following are strong electrolytes? Hcl hc2h3o2 nh3 kcl
Arturiano [62]
<h3><u>Answer;</u></h3>

HCl and KCl

<h3><u>Explanation</u>;</h3>
  • Strong electrolytes are strong bases and acids.
  • HCl is a strong acid; it dissociates completely to form H+ and Cl- ions. Thus, it is a strong, rather than weak, electrolyte.
  • CH3COOH is acetic acid, a weak acid. Only some of it will dissociate (to H+ and acetate ions), thus, it will only be a weak electrolyte.
  • NH3 will react with water as a weak base: NH3 + H2O → NH4+ + OH-. It will thus also be a weak electrolyte.  
  • KCl is a soluble ionic compound, and as such, it will be a strong electrolyte.
5 0
3 years ago
Read 2 more answers
What gets reduced in an electrolytic cell made with nickel and copper electrodes?
jekas [21]

Answer:

D. Ni²⁺  

Explanation:

We know at once that the answer cannot be A or C, because Ni and Cu are already in their lowest oxidation states.

The correct answer must be either B or D.

An electrolytic cell is the opposite of a galvanic cell. In the former, the reaction proceeds spontaneously. In the latter, you must force the reaction to occur.  

One strategy to solve this problem is:

  1. Look up the standard reduction potentials for the half reaction·
  2. Figure out the spontaneous direction.
  3. Write the equation in the reverse direction.

1. Standard reduction potentials

                                E°/V

Cu²⁺ + 2e⁻ ⟶ Cu; 0.3419

Ni²⁺ + 2e⁻ ⟶ Ni;  -0.257

2. Galvanic Cell

We reverse the direction of the more negative half cell and add.

                                       <u>E°/V </u>

Ni ⟶ Ni²⁺ + 2e⁻;           0.257

<u>Cu²⁺ + 2e⁻ ⟶ Cu;      </u>   0.3419

Ni + Cu²⁺ ⟶ Cu + Ni²⁺; 0.599

This is the spontaneous direction.

Cu²⁺ is reduced to Cu.

3. Electrochemical cell

                                        <u>E°/V</u>

Ni²⁺ + 2e⁻ ⟶ Ni;           -0.257

<u>Cu ⟶ Cu²⁺ + 2e⁻;        </u> <u>-0.3419</u>

Cu + Ni²⁺ ⟶ Ni + Cu²⁺; -0.599

This is the non-spontaneous direction.

Ni²⁺ is reduced to Ni in the electrolytic cell.

8 0
3 years ago
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