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Zepler [3.9K]
3 years ago
13

According to Reaction B, how many moles of B2(SO3)3 can be formed from 9.31 moles of LiF?

Chemistry
1 answer:
oksian1 [2.3K]3 years ago
5 0
Sorry bro I don’t know the answer plz search in browser
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What term is defined as the number of moles of solute divided by the number of liters of solutions?
hoa [83]

The molar concentration of the solution.

6 0
3 years ago
Explain the regiochemistry of the Friedel-Crafts alkylation of 1,4-dimethoxybenzene. There are three positions available for the
defon

Answer:

In an electrophilic aromatic substitution (Friedel Crafts alkylation) first in the monoalkylation of the 1,4-dimethoxybenzenethe the methoxy groups redirects the substitution for ortho-para positions with respect to the electrophile that is going to enter (alkyl group) this is due to the increase in electron density in that position, that is , to the inductive effect.

According to the second incoming alkyl group there would be 3 positions available, from which it will choose the meta position in relation to the second methoxy group, since the alkyl group is a weak activator of the ortho meta positions and coincides with the position to which it redirects the second methoxy group.

7 0
3 years ago
During a combustion reaction, 9.00 grams of oxygen reacted with 3.00 grams of CH4.
Monica [59]

Answer:

0.74 grams of methane

Explanation:

The balanced equation of the combustion reaction of methane with oxygen is:

  • CH₄ + 2 O₂ → CO₂ + 2 H₂O

it is clear that 1 mol of CH₄ reacts with 2 mol of O₂.

firstly, we need to calculate the number of moles of both

for CH₄:

number of moles = mass / molar mass = (3.00 g) /  (16.00 g/mol) = 0.1875 mol.

for O₂:

number of moles = mass / molar mass = (9.00 g) /  (32.00 g/mol) = 0.2812 mol.

  • it is clear that O₂ is the limiting reactant and methane will leftover.

using cross multiplication

1 mol of  CH₄ needs → 2 mol of O₂

???  mol of  CH₄  needs → 0.2812 mol of O₂

∴ the number of mol of CH₄ needed = (0.2812 * 1) / 2 = 0.1406 mol

so 0.14 mol will react and the remaining CH₄

mol of CH₄ left over = 0.1875 -0.1406 = 0.0469 mol

now we convert moles into grams

mass of CH₄ left over = no. of mol of CH₄ left over *  molar mass

                                    = 0.0469 mol * 16 g/mol = 0.7504 g

So, the right choice is 0.74 grams of methane

3 0
3 years ago
An Asteroid is smaller than a planet but larger than a meteoroid? True or false pls no files or links they DO NOT WORK!!!!
velikii [3]

Answer:

true astroids are in space and are bigger than meteorites but smaller than planets, meteorites which are asteroids after landing on earth and losing most of its mass on its way

4 0
3 years ago
How did oxygen (O2) get into Earth's atmosphere? How did oxygen (O2) get into Earth's atmosphere? It was captured from the solar
Ugo [173]

Answer:

Option (4)

Explanation:

The primitive atmosphere was comprised of lesser or no amount of oxygen. With the progressive time, primitive organisms appeared such as the primitive aquatic plants, algae, and cyanobacteria, that carried out the process of photosynthesis in the presence of sunlight, water, and CO₂, and in return produced the food and oxygen. This is how the rapid photosynthesis process led to the increasing amount of oxygen in the atmosphere that facilitates the growth and evolution of different life forms on earth.

Thus, the correct answer is option (4).

3 0
3 years ago
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