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ladessa [460]
3 years ago
10

What is the solution of this linear system? x+y=13

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0

Answer:

The solution of the linear equation is: (6,7)

Step-by-step explanation:

This being that:

x + y = 13

1/2x + y = 10

What you do in order to find the solution is either (2 ways):

- Substitution

- Elimination

I'm sure that either way, you'll get the same thing. I used: Substitution.

To do this choose either if you want to find [x] or [y] first, then substitute it in. I will choose to find [x] first.

<h2>x + y = 13</h2><h2><u>           - y </u>    </h2><h2>x = 13 - y</h2>

Now substitute it into:  

1/2x + y = 10

1/2(13 - y) + y = 10

1/2(13 -y) + y= 10

<h2>Then to get rid of fraction, instead of dividing, you multiply with reciprocal</h2><h2>1/2 · 2/1 (They cancel out) Leaving you with:</h2><h3 /><h3>(13 - y) 2(y) = 2(10)</h3><h3>(Everything is multiplied, except for 13 - y, because it had parenthesis to protect it.)</h3><h3>13 - y + 2y = 20</h3><h3 /><h2>13 + y = 20</h2><h2><u>- 13       - 13</u></h2><h2>           <u>y = 7</u></h2><h2 /><h2>You now have your [y] for your coordinate.</h2><h2>(x, 7), now time to find your [x]</h2><h2 />

Now you substitute your [y] into your equation:

1/2x + (7) = 10

<h2>1/2x + 7 = 10</h2><h2><u>          -7 = -7</u></h2><h2>1/2x = 3</h2><h2>(To get rid of fraction, multiply on both sides with reciprocal)</h2><h2>1/2 cancels out with 2/1</h2><h2>x = 2(3)</h2><h2>x = 6</h2><h2>You now have your [x] coordinate.</h2><h2 /><h2>This is your coordinate: </h2><h2>(6,7)</h2><h2></h2>

 

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<span>3x + y = 9 (I)
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------------------------
</span>\left \{ {{3x + y = 9 } \atop {y = -4x + 10 }} \right.

Pass the incognito "4x" to the first term, changing the signal when changing sides.
<span>-------------------------
simplify by (-1)
</span>\left \{ {{3x + y = 9.(-1)} \atop {4x + y = 10 }} \right.<span>

-------------------------
</span>\left \{ {{- 3x - \diagup\!\!\!\!y =-9} \atop {4x + \diagup\!\!\!\!y = 10}} \right.     &#10;
<span>
-------------------------
</span>\left \{ {{- 3x = - 9} \atop {4x = 10}} \right.<span>

-----------
</span>\boxed{x = 1}<span><span>

</span></span><span>Substitute in equation (I) to find the value of "Y".

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Answer:
\boxed{\boxed{ \left \ {{x=1} \atop {y=6}} \right. }}

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