the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Multiply both sides of the equation by 12
You have to divide to find a common number. 143/13=11
1:11
Use order of operations.
-23-20-(-17)+(-5)x(-2)+4x5
Do all multiplication steps.
-23-20-(-17)+10+20
Do all addition and subtraction steps fro left to right.
-43-(-17)+10+20
-26+10+20
-16+20
answer: 4
Answer:
c
Step-by-step explanation:
when you multiply 25* 7 you get 175 then you divide it by 60 which gives you 2.911 so its 2 hours and 55 min. I hope that was right and that was helpful
