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masha68 [24]
3 years ago
9

To transmit information on the internet, large files are broken into packets of smaller sizes. Each packet has 1,500 bytes of in

formation. An equation relating packets to bytes of information is given by b=1,500p where p represents the number of packets and b represents the number of bytes of information.
How many packets would be needed to transmit 30,000 bytes of information?
How much information could be transmitted in 30,000 packets?
Each byte contains 8 bits of information. Write an equation to represent the relationship between the number of packets and the number of bits.
Mathematics
1 answer:
Alexeev081 [22]3 years ago
7 0

Answer:

Step-by-step explanation:

Jjhu

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Find the measurements (the length L and the width W) of an inscribed rectangle under the line with the 1st quadrant of the x &am
Leni [432]

The question is incomplete. Here is the complete question.

Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -\frac{3}{4}x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.

Answer: L = 1; W = 9/4; A = 2.25;

Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:

A = x.y

A = x(-\frac{3}{4}.x + 3)

A = -\frac{3}{4}.x^{2}  + 3x

To maximize, we have to differentiate the equation:

\frac{dA}{dx} = \frac{d}{dx}(-\frac{3}{4}.x^{2}  + 3x)

\frac{dA}{dx} = -3x + 3

The critical point is:

\frac{dA}{dx} = 0

-3x + 3 = 0

x = 1

Substituing:

y = -\frac{3}{4}x + 3

y = -\frac{3}{4}.1 + 3

y = 9/4

So, the measurements are x = L = 1 and y = W = 9/4

The maximum area is:

A = 1 . 9/4

A = 9/4

A = 2.25

6 0
3 years ago
Sketch the curve y=(3x-4)(4x-3)^2
Katyanochek1 [597]
Google has the complete curve of the graph. just search this- <span>y=(3x-4)(4x-3)^2 and it shows. 

Hope this helps!</span>
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3 years ago
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