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katrin2010 [14]
3 years ago
14

A construction crew has just finished building a road. the crew worked for 10 days. if they build 2 3/4 kilometers of road each

day, what is the total length of road they built?
Mathematics
2 answers:
sergey [27]3 years ago
8 0

Answer:

The length made in 10 days is 27\frac{1}{2} kilometers.

Step-by-step explanation:

Total number of days the crew worked = 10

Length of road built each day = 2\frac{3}{4} or \frac{11}{4} kilometers

So, total length of road made in 10 days will be :

\frac{11}{4}\times10=\frac{110}{4}

= 27.5 kilometers.

In fraction form we can write as :

27\frac{1}{2} kilometers.

tatuchka [14]3 years ago
7 0
2.75 x 10 = 27.5 or 27 1/2 kilometers total
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The length is _____ the width is______ and the area of the actual room is ___ _______
RSB [31]

Answer:

98 square inches.

Step-by-step explanation:

The length is 14 inches. The width is 7 inches.

7 * 14 = 98 square inches.

The area is 98 square inches.

8 0
3 years ago
Find the surface area of the prism.
ratelena [41]
The surface area would be 3 times 4 which is 12cm3
5 0
2 years ago
Devon and his friends bought strawberry wafers for $3 per packet and chocolate wafers for $1 per packet at a carnival. They spen
Irina-Kira [14]
Hi there!

PART A:
The system of equations we would use would be:
x + y = 22 (amount of items)
3x + 1y = 30 (cost)

Variables:
x = the amount of strawberry wafers bought at the price of $3
y = the amount of chocolate wafers bought at the price of $1

PART B:
To solve, we'll use substitution because we can easily isolate a variable using the first equation.

Work:
x + y = 22 (first equation)
y = 22 - x (isolating a variable)
3x + 1y = 30 (second equation)
3x + (22 - x) = 30 (substituting into the second equation)
2x + 22 = 30 (simplifying)
2x = 8 (subtracting)
x = 4 strawberry wafers
4 + y = 22 (substituting x into the first equation to solve for y)
y = 18 chocolate wafers

ANSWER:
They bought 4 strawberry wafers and 18 chocolate wafers.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
8 0
3 years ago
Suppose that $a$ is a positive integer for which the least common multiple of $a+1$ and $a-5$ is $10508$. What is $a^2 - 4a + 1$
Nana76 [90]

Answer:

21022.

Step-by-step explanation:

Find the prime factors of 10508:

2 ) 10508

2 ) 5254

37 ) 2627

       71.

50208 = 2*2*37*71.

Now there is no integer value for a that would fit  (a+ 1)(a - 5) = 10508 .

But we could try multiplying the LCM by 2:-

= 21016  = 2*2*2*37*71.

= 2*2*37 multiplied by 2 * 71

= 148 * 142.

That looks promising!!

a - 5 = 142 and

a + 1 = 148

This gives  2a - 4 = 290

2a = 294

a = 147.

So substituting a = 147 into a^2 - 4a + 1 we get:

= 21022.

4 0
3 years ago
Gabrielle is 3 times older than mikhail. the sum of their ages is 80. how old is mikhail
skelet666 [1.2K]
The sum of their ages equals 80.
Gabrielle is 3 times older than Mikhail

Two numbers that have a sum of 80, with one number being 3 times the other are:
Gabrielle’s age: 60
Mikhail’s age: 20

60 + 20 = 80
20 x 3 = 60


Mikhail is 20 years old.

4 0
3 years ago
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