1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
masya89 [10]
3 years ago
11

Alicia has 32 stickers this is 4 times as many stickers as Benita has how many stickers does Benita have

Mathematics
2 answers:
Korvikt [17]3 years ago
8 0
Benita has 128 stickers because 32*4
Nikitich [7]3 years ago
7 0
32 divided by 4 is 8. Benita has 8 stickers
You might be interested in
HELPP ME<br> s + 3 Five6= 6 17
Oduvanchick [21]

Answer:The crystal structures of five 6-mercaptopurine derivatives, viz. 2-[(9-acetyl-9H-purin-6-yl)sulfan­yl]-1-(3-meth­oxy­phen­yl)ethan-1-one (1), C16H14N4O3S, 2-[(9-acetyl-9H-purin-6-yl)sulfan­yl]-1-(4-meth­oxy­phen­yl)ethan-1-one (2), C16H14N4O3S, 2-[(9-acetyl-9H-purin-6-yl)sulfan­yl]-1-(4-chloro­phen­yl)ethan-1-one (3), C15H11ClN4O2S, 2-[(9-acetyl-9H-purin-6-yl)sulfan­yl]-1-(4-bromo­phen­yl)ethan-1-one (4), C15H11BrN4O2S, and 1-(3-meth­oxy­phen­yl)-2-[(9H-purin-6-yl)sulfan­yl]ethan-1-one (5), C14H12N4O2S. Compounds (2), (3) and (4) are isomorphous and accordingly their mol­ecular and supra­molecular structures are similar. An analysis of the dihedral angles between the purine and exocyclic phenyl rings show that the mol­ecules of (1) and (5) are essentially planar but that in the case of the three isomorphous compounds (2), (3) and (4), these rings are twisted by a dihedral angle of approximately 38°. With the exception of (1) all mol­ecules are linked by weak C—H⋯O hydrogen bonds in their crystals. There is π–π stacking in all compounds. A Cambridge Structural Database search revealed the existence of 11 deposited compounds containing the 1-phenyl-2-sulfanyl­ethanone scaffold; of these, only eight have a cyclic ring as substituent, the majority of these being heterocycles.

Keywords: crystal structure, mercaptopurines, supra­molecular structure

Go to:

Chemical context  

Purines, purine nucleosides and their analogs, are nitro­gen-containing heterocycles ubiquitous in nature and present in biological systems like man, plants and marine organisms (Legraverend, 2008 ▸). These types of heterocycles take part of the core structure of guanine and adenine in nucleic acids (DNA and RNA) being involved in diverse in vivo catabolic and anabolic metabolic pathways.

6-Mercaptopurine is a water insoluble purine analogue, which attracted attention due to its anti­tumor and immunosuppressive properties. The drug is used, among others, in the treatment of rheumathologic disorders, cancer and prevent

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Evaluate the expression 4⋅f(6)−6⋅g(5)
sladkih [1.3K]

Answer:

send full question

Step-by-step explanation:

4 0
3 years ago
If he has total of 20 fish,how many guppies does he have?
BaLLatris [955]

He has 20 guppies?

This is what I got from the information. Unless they had eggs.

3 0
3 years ago
A coat manufacturer puts 104 coats in a shipment they sent out 41 shipments how many coats did they manufacture send out
Grace [21]

Answer:

The answer is 4,264.

Step-by-step explanation:

6 0
3 years ago
A point in the figure is selected at random. Find the probability that the point will be in the part that is NOT shaded.
Dovator [93]

Answer:

B

Step-by-step explanation:

So the question really is what is the probability that the point is in the square? You cannot pick something surrounding the circles because you do not know anything about that region.

This is solved by comparing areas. There are 2 full circles there. 1 circle has an area of pi*r^2

Total shaded area = 2 * pi * r^2.

Let r = 3   This is a completely random choice. No matter what number you choose for r, the answer will come out the same. When you get along a little further in math, you will find that you can just use letters.

Total shaded area = 2 * 3.14 * 3^2

Total shaded area = 2 * 3.14 * 9

Total shaded area = 56.55

Total area of the square.

s = 2*r

s = 2*3

s = 6

Area of the square = 6^2 = 36

Total area of both regions = 56.55 + 36 = 92.55

Answer

% = (area of square) * 100% / Total area of both regions

% = 3600 / 92

% = 39%

Obviously the answer I get is not offered. The closest answer is B so I will choose that.

==========================

This is how this question would be done without using any value for r.

Area of shaded region = 2 pi r^2 = 6.28 r^2

Area of square  = d^2 where d = 2r

Area of square = 4 r^2

Total area = 6.28 r^2 + 4r^2 = 10.28 r^2

Area of square to total = (4r^2/10.28 r^2 ) * 100%

Area of square to total (as a %) = 4/10.28  * 100 = 39% which gives the same answer.

7 0
3 years ago
Read 2 more answers
Other questions:
  • Fredrick threw a ball from the top of a building. The height of the ball, in feet, after it is thrown is modeled by the function
    15·1 answer
  • Identify the geometric shape that is represented by the orthogtraphic drawing
    11·1 answer
  • 2882/2884 as a fraction
    15·1 answer
  • Generally what do the elements in a group have in common with each other?
    6·1 answer
  • Will mark branliest answer if gotten right!!!!!
    14·1 answer
  • LITERALLLLLLY DO AT 12
    9·2 answers
  • Anyone know how to do this? I need an answer fast show work please it’s 11:19 for me in California in 40 minutes I won’t need th
    5·2 answers
  • You have a 1 in 4 chance of winning a game. How would you calculate the probability that you will win 3 times in a row?
    12·2 answers
  • HELP ME?!?!?
    11·2 answers
  • I need help and can you show me the work because I still don't get it.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!