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siniylev [52]
3 years ago
5

What made the Fertile Crescent a good place for growing crops

Physics
2 answers:
Hunter-Best [27]3 years ago
6 0

Answer:

The Fertile Crescent was good for farming because of the fertility of its land, a result of irrigation from numerous large rivers in the region.

Explanation:

astraxan [27]3 years ago
6 0
Whatever the person above said or under said
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A 60-kg rollerblader rolls 10 m down a 30? incline. When she reaches the level floor at the bottom, she applies the brakes. The
VARVARA [1.3K]

Answer:

s = 20 m

Explanation:

given,

mass of the roller blader = 60 Kg

length = 10 m

inclines at = 30°

coefficient of friction = 0.25

using conservation of energy

\dfrac{1}{2}mu^2 = m g d sin \theta

u^2 = 2 g d sin30^0

u= \sqrt{2\times 9.8 \times 10 sin30^0}

u = 9.89 m/s

Using second law of motion  

ma =μ mg

a = μ g

a = 0.25 x 9.8

a = 2.45 m/s²

Using third equation of motion ,  

v² - u² = 2 a s

0² - 9.89² = 2 x 2.45 x s

s = 20 m

the distance moved before stopping is 20 m

3 0
3 years ago
Top-down processing is often used when one encounters an unfamiliar stimulus. Please select the best answer from the choices pro
Naddik [55]
The answer for this question would be B) False or the second option because top-down processing is NOT often used when one encounters an unfamiliar stimulus.
7 0
3 years ago
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Explain why a doctor might not give you any medication if you have a viral disease?
fomenos

Answer:

You never know if the medication could make you worse

Explanation:

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There are two main groups of recyclable material,
Illusion [34]

Answer:Paper and plastic!

Explanation:

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3 years ago
What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of – 30.0 nC?
Nastasia [14]

Answer:

F=1.26*10^{-3}N

Explanation:

Assuming the pith balls as point charges, we can calculate the repulsive force between them, using Coulomb's law:

F=\frac{kq_1q_2}{d^2}

We observe that the magnitude of the electric force is directly proportional to the product of the magnitude of both signed charges(q_1,q_2) and inversely proportional to the square of the distance(d) that separates them.

Replacing the given values, where k is the Coulomb constant:

F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-30*10^{-9}C)(-30*10^{-9}C)}{(8*10^{-2}m)^2}\\F=1.26*10^{-3}N

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3 years ago
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