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3 years ago

If h(x) = (f o g)(x) and h(x) = ∛7x+1, find f(x) and g(x)

1 answer:

7 0

There's more than one way to combine them really
but an obvious one will be

$\bf \begin{array}{llll}
h(x)&=&(f\circ g)(x)\\\\
&&\sqrt[3]{7x+1}\\\\
&&\sqrt[3]{g(x)}\leftarrow 
\begin{array}{llll}
f(x)=\sqrt[3]{x }\\\\
g(x)=7x+1
\end{array}
\end{array}\\\\
-----------------------------\\\\
(f\circ g)(x)\iff f[\quad g(x)\quad ]=\sqrt[3]{g(x)}\implies f[\quad g(x)\quad ]=\sqrt[3]{7x+1}$

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What are the solutions to the following system?

bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

$y=-3 x^{2}+5$ (given) -------- (2)

Equate (1) and (2).

$-5+2 x^{2}=-3 x^{2}+5$

Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

$-5+5x^{2}=5$

Add 5 on both sides.

$-5+5x^{2}+5=5+5$

$5x^{2}=10$

Divide by 5 on both sides, we get

$x^{2}=2$

Taking square root on both sides, we get

$x=\sqrt{2}, x=-\sqrt{2}$

Substitute $x=\sqrt{2}$ in (1).

$y=-5+2(\sqrt{2})^2$

$y=-5+4$

$y=-1$

Substitute $x=-\sqrt{2}$ in (1).

$y=-5+2(-\sqrt{2})^2$

$y=-5+4$

$y=-1$

Therefore the solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Option C is the correct answer.

6 0

3 years ago

A. 3 <br>B. 10<br>C. 20<br>D. 30

Dahasolnce [82]

<u>Answer:</u>

<u>Explanation:</u>

292/100×9.9 = 2.92×9.9 = <u>28.908</u>

30 is closest to 28.908

3 0

3 years ago

Write equations for the horizontal and vertical lines passing through the point (8,5)

almond37 [142]

Answers:

Horizontal Line: y = 5

Vertical Line: x = 8

=================================================

Explanation:

All horizontal lines are of the form y = k, for some constant k. We want the horizontal line to pass through (8,5), meaning every point on this horizontal line must have y coordinate 5. Therefore, y = 5 is the equation of the horizontal line. Two such points on this line are (1, 5) and (8, 5). All that matters is the y coordinate is 5. The x coordinate can be anything you want. The slope of any horizontal line is 0.

Flipping things around, all vertical lines will have the x coordinate of each point be the same value. Draw a vertical line through (8,5) and note how each point has x coordinate of 8. Two such points are (8,1) and (8,5). Therefore, the equation of the vertical line is x = 8. The y coordinate can be any value you want. The slope of any vertical line is undefined. Unlike the horizontal line, we cannot write this equation in slope intercept form (namely because the slope isn't defined).

7 0

3 years ago

suppose a regulation changes the cost of the taxi ride to $1.80 per mile, plus a fee of $4.30. How does the price of the 6.5 mil

Westkost [7]

$11.70 would be the cost of the ride without the plus fee added on. with the fee of $4.30 added on, the total cost would come to be $16.00

6 0

3 years ago

A toy rocket is launched from a platform 33 feet above the ground at a speed of 83 feet per second. The height of the rocket in

yanalaym [24]

Answer:

c. 138 feet

Step-by-step explanation:

h(t) = −16t^2 + 83t + 33

At3 seconds

h(3) = -16(3^2) + 83(3) + 33

h(3) = -16(9) + 249 + 33

h(3) = -144 + 249 + 33

h(3) = 138

c. 138 feet

3 0

2 years ago