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Klio2033 [76]
3 years ago
11

The scientific method is critical to scientific study. In an essay, discuss the possible use of the scientific method in everyda

y life and how it might be important. Please include the steps of the scientific method. You can incorporate a previous lab, i.e. Rolling balls lab into your steps
Chemistry
1 answer:
Eduardwww [97]3 years ago
6 0

Scientific method consists of systematic observation, hypothesis, and experimentation of observation and hypothesis.

Explanation:

  • Scientific method and steps can be explained by an example. Suppose you live in a sea side and in your house compound, you have a pond. You observe that during winter, pond freezes while the sea doesn't.
  • You think about it and reach the hypothesis that it may be because sea water that is salty has a higher freezing point than pond water, which is fresh water.
  • You experiment and prove your hypothesis by taking two cups of distilled water and pouring salt to one of it. You keep them in refrigerator and  increase the freezing point. You see the distilled water cup getting frozen and the other cup is not because the salty water in it has a higher freezing point.
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When 6.040 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 18.95 grams of CO2 and 7.759 grams of H
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Answer: The empirical formula is CH_2 and molecular formula is C_4H_8

Explanation:

We are given:

Mass of CO_2 = 18.95 g

Mass of H_2O= 7.759 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, =\frac{12}{44}\times 18.59=5.07g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 7.759 g of water, =\frac{2}{18}\times 7.759=0.862g of hydrogen will be contained.

Mass of C = 5.07 g

Mass of H = 0.862 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.422}{0.422}=1

For H =\frac{0.862}{0.422}=2

The ratio of C : H = 1: 2

Hence the empirical formula is CH_2.

The empirical weight of CH_2 = 1(12)+2(1)= 14 g.

The molecular weight = 56.1 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4

The molecular formula will be=4\times CH_2=C_4H_8

6 0
3 years ago
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