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Pepsi [2]
3 years ago
14

2. Which substance will form a solution with water? (Select all that app

Chemistry
1 answer:
cupoosta [38]3 years ago
7 0

Answer:

sugar and salt, as they can dissolve in water. Sugar and salt have a high solubility in water. So, sugar and salt can form a solution with water.

Explanation:

You might be interested in
Fe2O3 + H2 --> Fe + H2O
sveticcg [70]
A) 10.0g of Iron is \frac{10.0}{55.8}=179mmol of Iron.

One mole of dihydrogen is required to form one mole of iron, hence you'll need 0.179*1.00=0.179g of dihydrogen.

B) Likewise : 2.50g of Iron is \frac{2.50}{55.8}=44.8mmol of Iron, hence we'll need 44.8*(3*16+2*55.8)=7.15g of Fe2O3.
4 0
4 years ago
Plz do 108, 110, and 112! I really need help
Gennadij [26K]
Im sorry i can only do the last one the answer might be a, d, e. Im so sorry if im wrong
8 0
3 years ago
Read 2 more answers
Write the balanced chemical equation for each of these reactions. Include phases.
Ket [755]

<u>Answer:</u> The chemical equations are given below.

<u>Explanation:</u>

  • <u>For 1:</u>

The chemical equation for the reaction of lead nitrate and sodium hydroxide follows:

Pb(NO_3)_2(aq.)+2NaOH(aq.)\rightarrow Pb(OH)_2(s)+2NaNO_3(aq.)

By Stoichiometry of the reaction:

1 mole of aqueous solution of lead nitrate reacts with 2 moles of aqueous solution of sodium hydroxide to produce 1 mole of solid lead hydroxide and 2 moles of aqueous solution of sodium nitrate.

  • <u>For 2:</u>

The chemical equation for the reaction of lead hydroxide and hydroxide ions follows:

Pb(OH)_2(s)+2OH^-(aq.)\rightarrow [Pb(OH)_4]^{2-}(aq.)

By Stoichiometry of the reaction:

1 mole of lead hydroxide reacts with 2 moles of aqueous solution of hydroxide ions to produce 1 mole of aqueous solution of tetra hydroxy lead (II) complex

Hence, the chemical equations are given above.

4 0
3 years ago
Which process is responsible for bending and curving of rock layers
lapo4ka [179]
The answer is deformation of rocks. hope it helps :)
8 0
4 years ago
Read 2 more answers
A given reaction has an activation energy of 24.52 kj/mol. at 25°c, the half-life is 4 minutes. at what temperature will the hal
igor_vitrenko [27]
According to half life equation:

T(1/2) = ㏑2 / K1

when the T(1/2) = 4 min * 60 = 240 sec

by substitution:

240 = 0.6931 / K1

K1 = 2.9 x 10^-3

when the second T(1/2) = 20 sec, so to get K2:

T(1/2) = 0.6931 / K2

by substitution:

20 = 0.6931 / K2

∴K2 = 3.4 x 10^-2

so, we can get T2 by using this formula:

㏑ (K2/K1) = Ea/R (1/T1 - 1/T2)

by substitution:

㏑(3.4 x 10^-2)/(2.9 x 10^-3) = (24520 / 8.314) (1/298 - 1/T2)

∴ T2 = 396.7 K

         = 396.7 - 273 = 123.7 °C 



4 0
3 years ago
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