Given that for each <span>$2 increase in price, the demand is less and 4 fewer cars are rented.
Let x be the number of $2 increases in price, then the revenue from renting cars is given by
![(48 + 2x) \times (150 - 4x)=7,200+108x-8x^2](https://tex.z-dn.net/?f=%2848%20%2B%202x%29%20%5Ctimes%20%28150%20-%204x%29%3D7%2C200%2B108x-8x%5E2)
.
Also, given that f</span><span>or each car that is rented, there are routine maintenance costs of $5 per day, then the total cost of renting cars is given by
![5(150-4x)=750-20x](https://tex.z-dn.net/?f=5%28150-4x%29%3D750-20x)
Profit is given by revenue - cost.
Thus, the profit from renting cars is given by
</span><span>
![(7,200+108x-8x^2)-(750-20x)=6,450+128x-8x^2](https://tex.z-dn.net/?f=%287%2C200%2B108x-8x%5E2%29-%28750-20x%29%3D6%2C450%2B128x-8x%5E2)
For maximum profit, the differentiation of the profit function equals zero.
i.e.
</span><span>
![\frac{d}{dx} (6,450+128x-8x^2)=0 \\ \\ 128-16x=0 \\ \\ x= \frac{128}{16} =8](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdx%7D%20%286%2C450%2B128x-8x%5E2%29%3D0%20%5C%5C%20%20%5C%5C%20128-16x%3D0%20%5C%5C%20%20%5C%5C%20x%3D%20%5Cfrac%7B128%7D%7B16%7D%20%3D8)
The price of renting a car is given by 48 + 2x = 48 + 2(8) = 48 + 16 = 64.
Therefore, the </span><span>rental charge will maximize profit is $64.</span>
Answer:
2nd option will be the answer (y=4x²+48x+146)
Step-by-step explanation:
y=4(x+6)²+2
y=4(x²+2*x*6+6²)+2 [(a+b)²=a²+2ab+b²]
y=4(x²+12x+36)+2
y=4(x²)+4(12x)+4(36)+2
y=4x²+48x+144+2
y=4x²+48x+146
Answer:
D
Step-by-step explanation:
-9x-27+12 = -6x-15-3x
0=0
D) the equation has infinitely many solutions
Answer:
Answer: The mean increases by 3
Step-by-step explanation:
The original data set is
{50, 76, 78, 79, 79, 80, 81, 82, 82, 83}
The outlier is 50 because it is not near the group of values from 76 to 83 which is where the main cluster is.
The original mean is M = (50+76+78+79+79+80+81+82+82+83)/10 = 77
If we take out the outlier 50, the new mean is N = (76+78+79+79+80+81+82+82+83)/9 = 80
So in summary so far
old mean = M = 77
new mean = N = 80
The difference in values is N-M = 80-77 = 3
So that's why the mean increases by 3