Answer:
y₁=x₁+0.04x₂
y₂=x₂+0.06x₁
Step-by-step explanation:
In the first year, number of people who live:
In the city= x₁
In the suburb=x₂
New Population in the next year
In the city= y₁
In the suburb=y₂
If each year 6% of the city population moves to the suburb,
New Suburb Population=Previous Population+Immigrants
y₂=x₂+0.06x₁
If each year 4% of the suburb population moves to the city,
New City Population=Previous Population+Immigrants
y₁=x₁+0.04x₂
y₁=x₁+0.04x₂
y₂=x₂+0.06x₁
Answer:
The solution is:
![-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}](https://tex.z-dn.net/?f=-7r-4%5Cge%20%5C%3A%5C%3A4r%2B2%5Cquad%20%5C%3A%3A%5Cquad%20%5C%3A%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ar%5Cle%20%5C%3A%5C%3A-%5Cfrac%7B6%7D%7B11%7D%5C%3A%5C%5C%20%5C%3A%5C%3A%5Cmathrm%7BDecimal%3A%7D%26%5C%3Ar%5Cle%20%5C%3A%5C%3A-0.54545%5Cdots%20%5C%3A%5C%5C%20%5C%3A%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%5C%3A%2C%5C%3A-%5Cfrac%7B6%7D%7B11%7D%5D%5Cend%7Bbmatrix%7D)
Please check the attached line graph below.
Step-by-step explanation:
Given the expression
Add 4 to both sides
Simplify
Subtract 4r from both sides
Simplify
Multiply both sides by -1 (reverses the inequality)
Simplify
Divide both sides by 11
Simplify
Therefore, the solution is:
Please check the attached line graph below.
8^14 is the answer.
This is because since they both have the same base, the exponents could be added together if the numbers are multiplied together
Answer:
Step-by-step explanation:
Used PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
First Power, next Addition
We are given: On january 1, 2000 initial population = 67,255.
Number of people increase each year = 2935 people.
Therefore, 67,255 would be fix value and 2935 is the rate at which population increase.
Let us assume there would be t number of years after year 2000 and population P after t years is taken by function P(t).
So, we can setup an equation as
Total population after t years = Number of t years * rate of increase of population + fix given population.
In terms of function it can be written as
P(t) = t * 2935 + 67255.
Therefore, final function would be
P(t) = 2935t +67255.
So, the correct option is d.P(t) = 67255 + 2935t.
