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3 years ago

The price of a notebook was $3.90 yesterday. Today, the price fell to $3.40

Mathematics

1 answer:

il63 [147K]3 years ago

4 0

Yesterday = 3.90
Today = 3.40
Decrease = 0.50

Percentage = 0.50/3.90*100%
= 12.82 %
Almost 13%

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12 - 15 / 3 - 3. Simplify

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Step-by-step explanation:

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2 years ago

What is the theoretical probability that a coin toss results in two heads showing?

Bond [772]

Since it's not mentioned I assume the Event of tossing a die twice are done simultaneously.

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4- What is the theoretical probability that a coin toss results in one head and one tail showing? If you get one Head, P(H) =1/2 and if you want a tail in the 2nd toss P(1/2). So P(one Head AND one tail) = 1/2 x 1/2 = 1/4

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3 years ago

Read 2 more answers

A textile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean thread elongation of 12 ki

MakcuM [25]

Answer:

P-value = 0.02275

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 12 kilograms

Sample mean, $\bar{x}$ = 11.5 kilograms

Sample size, n = 4

Alpha, α = 0.05

Population standard deviation, σ = 0.5 kilograms

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 12\\H_A: \mu < 12$

We use one-tailed(left) z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{11.5 - 12}{\frac{0.5}{\sqrt{4}} } = -2$

We calculate the p-value from the standard z-table:

P-value = 0.02275

5 0

3 years ago

An astronaut drops a rock into a crater of the moon. The distance, d(t), in meters, the rock travels after t seconds can be mode

ASHA 777 [7]

The average rate of change of the position of an object with respect to time is the average speed of the object, so to find the average speed of the rock over the interval [5,10], we are going to use the average rate of change formula: $V(t)= \frac{d(b)-d(a)}{b-a}$
where
$V(t)$ is the average rate of change (the speed)
$d(a)$ is the position function evaluated at $a$
$d(b)$ is the position function evaluated at $b$
$a$ is the first point in the interval
$b$ is the second point in the interval

We know for our problem that the first point in the interval is 5 and the second point is 10, so $a=5$ and $b=10$ . Lets replace those values in our formula:
$V(t)= \frac{d(b)-d(a)}{b-a}$
$V(t)= \frac{d(10)-d(5)}{10-5}$
$V(t)= \frac{0.8(10^2)-0.8(5^2)}{10-5}$
$V(t)= \frac{80-20}{5}$
$V(t)= \frac{60}{5}$
$V(t)=12$

We can conclude that the speed of the rock between 5 and 10 seconds is 12 meters per second.

4 0

3 years ago