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kobusy [5.1K]
3 years ago
10

What is the speed of a bobsled whose distance-time graph indicates that it traveled 107m in 27s?

Physics
1 answer:
Snowcat [4.5K]3 years ago
8 0
V=D/T
V=107 m / 27 s - divide distance by time
V= 4 m/s - because when we round 3.9629 in the nearest 10th we will get 4. 
Hope this helps

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A silver bar 0.125 meter long is subjected to a temperature change from 200°C to 100°C. What will be the length of the bar after
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\Delta L=  \alpha L_0 (T_f-T_i)

= (18 x 10^-6 /°C)(0.125 m)(100° C - 200 °C)

= -0.00225 m

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= 1.25 m + (-0.00225 m)
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A rope is used to pull a 5.07 kg block at constant speed 2.36 m along a horizontal floor. the force on the block from the rope i
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3 years ago
A 5.0 kg box slides down a 4.0 m long ramp that makes a 25 angle with the ground. If the coefficient of kinetic friction is 0.65
Sedaia [141]

The thermal energy was produced is 116J

<h3>What is the thermal energy produced?</h3>

Now we know that the frictional force produces the energy that is lost as heat as the body slides down the incline. The magnitude of the frictional force is obtained from;

Ff= μmgcosθ

Ff =  0.65 *  5.0 kg * 9.8 m/s^2 * cos 25

Ff = 29 N

Hence, the thermal energy is;

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Learn more about frictional force:brainly.com/question/1714663

#SPJ1

4 0
2 years ago
A lens of focal length 0.1 m is placed 0.08 m away from a bug. Where does the image of the bug appear to be (i.e., what is the i
tester [92]

Answer:

Image distance of the bug is - 0.4 m

Magnification is 5 times

Image is real and inverted

Solution:

As per the question:

The focal length of the lens, f = 0.1 m

Distance of the bud from the lens, v = 0.08 m

Now,

Using the lens maker formula:

\frac{1}{f} = \frac{1}{v} + \frac{1}{v'}

where

v' = distance of the bug's image from the lens

Now,

\frac{1}{v'} = \frac{1}{f} - \frac{1}{v}

\frac{1}{v'} = \frac{1}{0.1} - \frac{1}{0.08}

\frac{1}{v'} =  - \frac{1}{2.5}

v' = - 0.4 m

Now,

Magnification of the bug's image is given by:

m = \frac{-v'}{v}

m = \frac{-(- 0.4)}{0.08} = 5

Since, negative sign shows that inverted image is formed and positive value of magnification shows that real image is formed.

6 0
3 years ago
if 100 grams is equal to 1 newton of force, and the water displaced by an object would have a mass of 40 grams, what is its buoy
irina [24]

Let's take the actual question section all by itself:

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so that's the buoyant force acting on the object.


Now, to deal with the first phrase of the question ... everything before the first comma ... you said "100 grams is equal to 1 newton of force".  This phrase is really quite meaningless, and there's nothing to be done with it.

A quantity of mass is never "equal to" a force.

Fortunately, whatever this is supposed to mean, it's not needed to answer the rest of the question.

7 0
4 years ago
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