Answers:
Acceleration = 2.1875 m/s^2
Velocity after 2.5 seconds = 5.46875 m/s
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Work Shown:
Part 1
The mass is m = 3.2 and the force is F = 7.0
Apply the formula F = ma to find the acceleration to be...
F = ma
7.0 = 3.2*a
7.0/3.2 = a
2.1875 = a
a = 2.1875
The acceleration is 2.1875 m/s^2
Every second, the velocity of the plane is increasing by 2.1875 m/s.
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Part 2
We have the following variables
- vi = initial velocity = 0 m/s (since it starts from rest)
- vf = unknown final velocity (what we're trying to figure out)
- t = change in time = 2.5 seconds
- a = acceleration = 2.1875 m/s^2
Using one of the kinematics equations, we can then say,
vf = vi + a*t
vf = 0 + 2.1875*2.5
vf = 5.46875
After 2.5 seconds, the airplane is traveling 5.46875 m/s.
5.46875 m/s converts to roughly 12.2332 mph.
