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miskamm [114]
3 years ago
9

The atomic number of an element is found by counting the

Physics
1 answer:
QveST [7]3 years ago
6 0
By counting the protons in the element
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If you observe an impaired driver, a safe behavior for you would be ____________.
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Get someone else to drive me
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4 years ago
.. An object has a mass of 40 000 kilograms
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Answer:

8000 kg/cm^3

Explanation:

The density formula is P = M/V

Density = P = ? expressed in kg/m^3

M = mass = 40,000 kg

V = volume = 5 m^3

P = 40,000/5

P = 8000 kg/m^3

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if a body of mass 2kg travels with 2 m/s and other body of mass 2kg travels with 1m/s then find v1 and v2 in given statement​
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Answer:

Your answer is here,

Explanation:

v1 = 4 kg m/s

v2 = 2 kg m/s

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3 years ago
Oil having a specific gravity of 0.9 is pumped as illustrated with a water jet pump. The water volume flowrate is 1 m3 /s. The w
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Answer:

The rate at which the pump moves oil is 1 m³/s

Explanation:

Assumptions:

  • there is steady-state flow
  • oil and water are incompressible
  • first fluid is water, second fluid is oil and third fluid is the mixture of oil and water.

\rho_1Q_1 + \rho_2Q_2 = \rho_3Q_3 -------equation (i)

where;

ρ is the fluid density

Q is the volumetric flow rate

Q_1 + Q_2 = Q_3--------equation (ii)

Substitute in Q₃ in equation i

\rho_1Q_1 + \rho_2Q_2 = \rho_3(Q_1 +Q_2)

divide through by ρ₁

\frac{\rho_1Q_1}{\rho_1}+ \frac{\rho_2Q_2}{\rho_1} =\frac{ \rho_3(Q_1 +Q_2)}{\rho_1}\\\\Note; \frac{\rho_2}{\rho_1} = \gamma_2 \ and \ \frac{\rho_3}{\rho_1} = \gamma_3\\\\Q_1 + \gamma_2Q_2 = \gamma_3(Q_1+Q_2)

Make Q₂ the subject of the formula

Q_2 = \frac{Q_1(1- \gamma_3)}{\gamma_3-\gamma_2} = \frac{1 (\frac{m^3}{s}) (1-0.95)}{0.95-0.9} = 1 \ \frac{m^3}{s}

Therefore, the rate at which the pump moves oil is 1 m³/s

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3 years ago
(b) When petrol passes through a delivery pipe, electrostatic charge can build up as shown in the diagram.
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The answer is, If you're walking on the ice cream at 5 ounces per toaster, and your bicycle loses a sock, how much gravy will you need to repaint your hamster?
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