Answer:
49 m/s
Explanation:
This is the question from the document:
1. A bag dropped from a helicopter falls with an acceleration of 9.8m/s2. What is its velocity after 5s?
We can find the answer by using the equation a = (v-u) / t
Acceleration a = 9.81m/s2
initial velocity u = 0 m/s (the bag is only dropped, so there's no initial velocity already existing)
time t= 5s
final velocity v = unknown
9.8 = (v -0) / 5
v - 0 = 9.8x5
v = 49 m/s
reaction, opposite directions, and more
Answer:
10kN
Explanation:
Given data
m1= 50kg
u1= 3m/s
m2= 100kg
u2= 6m/s
v1= 2m/s
time= 0.04s
let us find the final velocity of Bruce v1
from the conservation of linear momentum
m1u1+m2u2=m1v1+m2v2
substitute
50*3+100*6= 50*v1+100*2
150+600=50v1+200
750-200=50v1
550= 50v1
divide both sides by 50
v1= 550/50
v1=11 m/s
From
F= mΔv/t
for Bruce
F=50*(11-3)/0.04
F=50*8/0.04
F=400/0.04
F=10000
F=10kN
for Max
F=100*(6-2)/0.04
F=100*4/0.04
F=400/0.04
F=10000
F=10kN
Answer:
750cm³
Explanation:
volume = length × width × height
15 × 10 × 5 = 750
750cm³
Answer:
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