Answer:
D. The friction force increases by 9600 N.
Explanation:
Frictional force is directly proportional to kinetic coefient of friction.
<span>So we wan't to know what is the velocity after a collision of two railroad cars, one moving to the east and the other moving to the west if m1=2000kg, v1=5m/s and m2=6000kg, v2=3m/s. We can find the solution using the law of conservation of momentum for plastic collisions that states that the momentum must remain constant before (left side of the equation) and after (right side of the equation) the collision: m1*v1+m2*v2=(m1+m2)*v. So now we simply plug in the numbers and get: 2000kg * 5m/s + 6000kg * 3m/s = (2000kg + 6000kg)*v. Now we can write: 10000 kgm/s + 18000 kgm/s = 8000kg * v. To get v, the velocity of both railroad cars after the collision we simply divide both sides of the equation with 8000 kg: so v=3.5m/s to the west. </span>
Answer:
The cars would both move in the direction with the greatest momentum. We know the truck would have the greatest momentum due to having the greatest mass. Plus, factors which affects momentum are mass and velocity.
Thus, the car would move forward towards the direction of momentum of the truck. Both will continue to move at the same velocity.
E.g. truck hits the back of a stationary car, both will move forward, to the right & travelling at the same speed, but lower than the initial velocity of the truck. Now the total the total momentum before the collision is the same as the total momentum after the collision; as a result, momentum has been conserved.
Hope this helps!
The net force on the toy is 0 Newton.
The mass of the toy is 2 kg.
The force F₁ is the tension applied by one of the siblings on the toy is 8N.
Let us assume that the force applied by the other sibling is F₂, which is produced by the acceleration is 4m/s².
We know,
Force = Mass x acceleration
Putting values,
F₂ = 2 x 4
F₂ = 8N.
As we know that the forces are in opposite directions because the toy is being pulled by both the siblings in their respective directions which are opposite to each other.
Hence, the net force F is given by,
F = F₁ - F₂
F = 8-8
F 0N.
Hence, there is no net force on the toy.
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<h2>
Answer: The half-life of beryllium-15 is 400 times greater than the half-life of beryllium-13.</h2>
Explanation:
The half-life of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.
In this case, we are given the half life of two elements:
beryllium-13:
beryllium-15:
As we can see, the half-life of beryllium-15 is greater than the half-life of beryllium-13, but how great?
We can find it out by the following expression:
Where is the amount we want to find:
Finally:
Therefore:
The half-life of beryllium-15 is <u>400 times greater than</u> the half-life of beryllium-13.