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3 years ago

Why are atoms electrically neutral?

Physics

1 answer:

Ghella [55]3 years ago

8 0

Because the electricity in the atoms are surrounded by the nucleus which is surrounded by the electron cloud

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A proton with charge 1.601019 As is moving at 2.4105 m/s through a magnetic field of 4.5 T. You want to find the force on the pr

Whitepunk [10]

The force on the proton is 17.4 N.

<h3>What is the force on the proton?</h3>

Now we know that the proton is positively charged and that the force on the charge as it moved through the magnetic field could be given by the relation; F = qvB

Where;

F = force

q = charge

v = velocity

B = magnetic field

Having said this, we can see that;

q = 1.601019 As or C

v = 2.4105 m/s

T = 4.5 T

F = 1.601019 As * 2.4105 m/s * 4.5 T

F = 17.4 N

Learn more about magnetic force:brainly.com/question/12824331

#SPJ1

6 0

1 year ago

What is the first sing of dehydration

Elodia [21]

Answer:Two early signs of dehydration are thirst and dark-coloured urine. This is the body's way of trying to increase water intake and decrease water loss.

Explanation:

6 0

3 years ago

Read 2 more answers

The blank is the core of an atom

alexdok [17]

Answer:

The <u>nucleus</u> is the core of an atom.

Step-by-step explanation:

That's just how it is.

5 0

3 years ago

When you rub your hands together, you cannot push harder on one hand than the other. can push harder on one hand than the other.

Sholpan [36]

I think it means that your putting in an equal amount of force on each hand because it's the same brain that controls what you do. I think that's what it means, not entirely sure but hope this helps

3 0

3 years ago

Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of -0.9537 N when separated by

scoray [572]

Answer:

<em>The initial charges on the spheres are </em> $6.796\ 10^{-6}\ c$ and $-3.898\ 10^{-6}\ c$

Explanation:

<u>Electrostatic Force </u>

Two charges q1 and q2 separated a distance d exert a force on each other which magnitude is computed by the known Coulomb's formula

$\displaystyle F=\frac{K\ q_1\ q_2}{d^2}$

We are given the distance between two unknown charges d=50 cm = 0.5 m and the attractive force of -0.9537 N. This means both charges are opposite signs.

With these conditions we set the equation

$\displaystyle F_1=\frac{K\ q_1\ q_2}{0.5^2}=-0.9537$

Rearranging

$\displaystyle q_1\ q_2=\frac{-0.9537(0.5)^2}{k}$

Solving for q1.q2

$\displaystyle q_1\ q_2=-2.6492.10^{-11}\ c^2\ \ ......[1]$

The second part of the problem states the spheres are later connected by a conducting wire which is removed, and then, the spheres repel each other with an electrostatic force of 0.0756 N.

The conducting wire makes the charges on both spheres to balance, i.e. free electrons of the negative charge pass to the positive charge and they finally have the same charge:

$\displaystyle q=\frac{q_1+q_2}{2}$