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pochemuha
3 years ago
7

I need help is it A B C or D

Mathematics
2 answers:
larisa86 [58]3 years ago
5 0
Its a
because you add 6x to the other side with the 42 which would look like 6x + 42
and divide by 2 on each side which equals  y \leq 3x+21
                                                                       
bonufazy [111]3 years ago
5 0
The xorrext answer is A
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Solve Square root of -144 =<br> -12i<br> -12<br> 12<br> 12i
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Answer:

12i

Step-by-step explanation:

Step 1: Write it out

√-144

Step 2: Factor

√144(√-1)

Step 3: Evaluate

12i

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90 over 100 is equivalent to what decimal
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3 years ago
A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple. How many ways are there to choose:(
Volgvan

Answer:

The number of ways of selecting of n items form r different items =^{(n+r-1)}C_{(r-1)}

A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple.

A) How many ways are there to choose 32 candies?

So, n = no. of items = 32

r = no. of types of items = 5

So, No. of ways to choose 32 candies = ^{(32+5-1)}C_{(5-1)}

                                                               = ^{36}C_{4}

                                                                 = \frac{36!}{4!(36-4)!}

                                                                 = 58905

So, No. of ways to choose 32 candies is 58905

B)32 candies with at least a piece of each flavor?

Out of 32 you choose 5 candies of different types

So, Remaining candies = 32 - 5 = 27

So, No. of ways to choose 27 candies = ^{(27+5-1)}C_{(5-1)}

                                                               = ^{31}C_{4}

                                                                 = \frac{31!}{4!(31-4)!}

                                                                 = 31465

So, No. of ways to choose 32 candies with at least a piece of each flavor is 31465

C) 32 candies with at least 4 cherry and at least 6 lemon?

So, you already choose 6+4= 10

So, remaining candies = 32-10 = 22

So, No. of ways to choose 22 candies = ^{(22+5-1)}C_{(5-1)}

                                                               = ^{26}C_{4}

                                                                 = \frac{26!}{4!(26-4)!}

                                                                 = 14950

Hence No. of ways to choose 32 candies with at least 4 cherry and at least 6 lemon is 14950

8 0
4 years ago
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