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jonny [76]
3 years ago
10

The square below represents one whole.

Mathematics
1 answer:
umka2103 [35]3 years ago
6 0

Fraction 44/100

Decimal .44

Percent 44%

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Ms. Jackson emptied 16 boxes of crayons into a classroom crayon bucket in each box 2/9 The crayons were green how many crayon bo
mote1985 [20]

Answer:

2 boxes

Step-by-step explanation:

do 16 times 2 you get 32 so there are 32 green crayons 32/9 9 times 3 is 36 which is over 32 so you cant fill 3 boxes 9 times 2 equals 27 so the answer would be she can fill 2 boxes

5 0
3 years ago
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Two angles are supplementary the measure of one angle is 4 times the measure of the other angle what is the measure of the small
noname [10]
X + y = 180
x = 4y 
Plug that in and you get: 4y + y = 180
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y = 36

If you want the larger angle, simply plug in y to x = 4y
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The smaller angle is 36 degrees, and the larger angle is 144 degrees.
7 0
3 years ago
a regular hexagonal nut of side 1 cm and length 3 cm with a central hole of diameter 1 cm. 3 cm 1 cm 1 cm. Calculate the volume
Bogdan [553]

Answer:

  5.44 cm³

Step-by-step explanation:

The volume of the hexagonal nut can be found by multiplying the area of the end face by the length of the nut. The end face area is the difference between the area of the hexagon and the area of the hole.

The area of a hexagon with side length s is given by ...

  A = (3/2)√3·s²

For s=1 cm, the area is ...

  A = (3/2)√3(1 cm)² = (3/2)√3 cm²

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The area of a circle is given by ...

  A = πr²

The radius of a circle with diameter 1 cm is 0.5 cm. Then the area of the hole is ...

  A = π(0.5 cm)² = 0.25π cm²

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The volume is the face area multiplied by the length, so is ...

  V = Bh = ((3/2)√3 -0.25π)(3) . . . . . cm³

  V = (9/2)√3 -0.75π cm³ ≈ 5.44 cm³

The volume of the metal is about 5.44 cm³.

5 0
2 years ago
I need the answer to 1+1 please
ycow [4]

Answer:

2

Step-by-step explanation:

8 0
3 years ago
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5(1-cos x)÷x<br> Determine the limit of the transcendental function (if it exists).
luda_lava [24]

hello here is a solution :

8 0
3 years ago
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