Answer:
<em>0.25</em>
Explanation:
According to newtons law of motion
\sum F_x = ma
F_f = ma
nR = ma
nmg = ma
ng = a
n = a/g
g is the acceleration due to gravity
Given
a = 2.42m/s²
g = 9.8m/s²
Substitute into the formula;
n = 2.42/9.8
n = 0.25
<em>Hence the coefficient of kinetic friction is 0.25</em>
<em></em>
Answer:
it evaporats
Explanation:
because the sun is so hot that the water will turn into gas hope i helped
Answer:
Vf = 60 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.

where:
Vf = final velocity [m/s]
Vi = initial velocity = 0
a = acceleration = 1 [m/s^2]
t = time = 60 [m]
Now replacing:
Vf = 0 + (1*60)
Vf = 60 [m/s]
A wave is like a transport of energy ( think sounds waves or light waves)
They can be measured by the amplitude and the wavelength
Answer:
Explanation:
A) <em>Large</em>: As she opens her parachute, she begins to displace a large volume of air. This leads to a Large air resistance
B) <em>increase, weight</em>: As she falls, the air resistance force <u><em>increases</em></u>. Now there is a force acting in opposite directions to her <u><em>weight.</em></u>
C)<em>Weight, Decelerate:</em> The skydiver has only the downward force of her <u><em>weight</em></u> pulling down on her, so she starts to <u><em>decelerate</em></u>
D) <em>Weight, Upward, Resultant</em>:
Her <u><em>weight </em></u>is now equal to the <u><em>upward </em></u>force from the ground. Her <u><em>resultant </em></u>force is then zero
E) <em>Increases, same, constant, resultant, terminal</em>:
As she accelerates faster, the air resistance force <u><em>increases</em></u>. It is now the <u><em>same </em></u>as her weight. She now moves at a <u><em>constant</em></u> speed because the <u><em>resultant </em></u>force acting on her is zero. She is now at her <u><em>terminal </em></u>velocity.
F) <em>Increases, same, constant, terminal</em>:
As she decelerates, the air resistance force on her parachute <u><em>increases </em></u>until it is the <u><em>same</em></u> as her weight. She is now moving with a <u><em>constant </em></u>speed until she hits the ground - a new slower <u><em>terminal</em></u> velocity