Question

As blood passes through the capillary bed in an organ, the capillaries join to form venules (small veins). If the blood speed increases by a factor of 4.00 and the total cross-sectional area of the venules is 10.0cm2, what is the total cross-sectional area of the capillaries feeding these venules?

Answer 1

Answer:

$A_2 = 2.5\ cm^2$

Explanation:

given,

velocity factor = 4

Cross-sectional area of venules(A₁) = 10 cm²

cross sectional area of capillaries(A_2) = ?

continuity equation = Q = AV

now,

$\dfrac{A_1}{A_2} = \dfrac{V_2}{V_1}$

$\dfrac{10}{A_2} =4$

$\dfrac{10}{4} =A_2$

$A_2 = 2.5\ cm^2$

hence, the area of capillaries is equal to 2.5 cm₂