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Elena-2011 [213]
3 years ago
11

As blood passes through the capillary bed in an organ, the capillaries join to form venules (small veins). If the blood speed in

creases by a factor of 4.00 and the total cross-sectional area of the venules is 10.0cm2, what is the total cross-sectional area of the capillaries feeding these venules?
Physics
1 answer:
Semenov [28]3 years ago
4 0

Answer:

A_2 = 2.5\ cm^2

Explanation:

given,

velocity factor = 4

Cross-sectional area of venules(A₁) = 10 cm²

cross sectional area of capillaries(A_2) = ?

continuity equation = Q = AV

now,

\dfrac{A_1}{A_2} = \dfrac{V_2}{V_1}

\dfrac{10}{A_2} =4

\dfrac{10}{4} =A_2

A_2 = 2.5\ cm^2

hence, the area of capillaries is equal to 2.5 cm₂

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The distance covered by car is equal to (assuming it is moving by uniform motion) the product between the car's speed and the time of the car ride, 4 h:
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Similarly, the distance covered by train is equal to the product between the train's speed and the duration of the train ride, 7 h:
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The total distance covered is S=255 km, which is the sum of the distances covered by car and train:
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If we put (2) into (1), we find
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