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Nonamiya [84]
3 years ago
11

a 4kg metal block absorbs 5000j of energy and increases to a temperature of 22°c. the metal has a specific heat capacity of 250j

/kg°c. what was the original temperature of the block?
Physics
1 answer:
e-lub [12.9K]3 years ago
6 0

Answer:

17 °C

Explanation:

From specific Heat capacity.

Q = cm(t₂-t₁)................. Equation 1

Where Q = Heat absorb by the metal block, c = specific heat capacity of the metal block, m = mass of the metal block, t₂ = final temperature, t₁ = Initial temperature.

make t₁ the subject of the equation

t₁ = t₂-(Q/cm)............... Equation 2

Given: t₂ = 22 °C, Q = 5000 J, m = 4 kg, c = 250 J/kg.°c

Substitute into equation 2

t₁ = 22-[5000/(4×250)

t₁ = 22-(5000/1000)

t₁ = 22-5

t₁ = 17 °C

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Oksana_A [137]

Answer:

The final velocity is 28.14 m/s

Yes the angle of projection matters

Explanation:

Given;

initial velocity of the water balloon, u = 20 m/s

height of the building, h = 20 m

let the final speed of the ball when it hits the ground = v

The final speed is calculated as follows;

v² = u² + 2gh

v² = (20)²  +  2(9.8)(20)

v² = 400 + 392

v² = 792

v = √792

v = 28.14 m/s

Yes the angle matters, if the balloon had been dropped at a certain angle, the final velocity would have been estimated using the following formula;

v_y^2 = u_y^2 sin^2(\theta) + 2gh_y

where;

θ is the angle of projection, which accounts for the vertical component of the velocity.

6 0
3 years ago
How long does it for a car to cover 100 miles at 60 mi/hr? Use one of the following equations:
yaroslaw [1]

Answer:

Explanation:

r = 60 mph

d = 100 miles

t = ?

t = d/r

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t = 1 2/3 hour or 1 hour and 40 minutes.

8 0
2 years ago
A submarine is stranded on the bottom of the ocean with its hatch 21.0 m below the surface. calculate the force (in n) needed to
Tanzania [10]

Answer:

28,400 N

Explanation:

Let's start by calculating the pressure that acts on the upper surface of the hatch. It is given by the sum of the atmospheric pressure and the pressure due to the columb of water, which is given by Stevin's law:

p_{top} = p_{atm} + \rho g h=1.013\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(21.0 m)=3.071 \cdot 10^5 Pa

On the lower part of the hatch, there is a pressure equal to

p_{bot}=p_{atm}=1.013\cdot 10^5 Pa

So, the net pressure acting on the hatch is

p=p_{top}-p_{bot}=3.071 \cdot 10^5 Pa - 1.013\cdot 10^5 Pa=2.058 \cdot 10^5 Pa

which acts from above.

The area of the hatch is given by:

A=\pi r^2 = \pi (\frac{0.420 m}{2})^2=0.138 m^2

So, the force needed to open the hatch from the inside is equal to the pressure multiplied by the area of the hatch:

F=pA=(2.058\cdot 10^5 Pa)(0.138 m^2)=28,400 N

8 0
3 years ago
HELP PLEASE 20 POINTS SHOW WORK, ALL EQUATIONS
nataly862011 [7]

Answer:

s = 3 m

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the position of the constant velocity and accelerating vehicles are

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t = 5.464 s

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300 cm when rounded to the single significant digit of the question numerals.

7 0
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mylen [45]

A snowball picks up speed as it rolls down the mountain.<em> (D)</em>

Since the description includes acceleration ("picks up speed"), we know that the forces on the snowball must be unbalanced.

3 0
3 years ago
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