9514 1404 393
Answer:
- square: 12 ft sides
- octagon: 6 ft sides
Step-by-step explanation:
This problem can be worked in your head.
If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.
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We can let s represent the side length of the octagon. Then we have ...
8s = perimeter of octagon
4(s +6) = perimeter of square
These are equal, so ...
4(s +6) = 8s
s +6 = 2s . . . . . . divide by 4
6 = s . . . . . . . . . . subtract s
The octagon has 6-ft sides; the square has 12-ft sides.
The distance between any 2 points P(a,b) and
Q(c,d) in the coordinate plane, is given by the formula:<span>
<span>
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Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.





Answer: B and D
Answer:
x = 2
Step-by-step explanation:
1. distribute 9 in 9(x+1)
9x + 9 = 25 + x
2. subtract x from the right side to isolate x onto one side
8x + 9 = 25
3. subtract 9 from the left side
8x = 16
4. divide both sides by 8 to get x alone
x = 2