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Rama09 [41]
3 years ago
5

How do you add single digit numbers

Mathematics
2 answers:
Vaselesa [24]3 years ago
6 0
Hi there!

This question isn't too hard.

To add with single digit numbers you just need to count.

You can regroup too, depending on what numbers you're using. I can give you some examples if you'd like!

1 + 2 = 3 because you need to just count. If I have one apple and you have two, count to see how many apples we have altogether. In this case, we have three apples.

What about 9 + 9? You would regroup because our answer is bigger than ten. If I have nine pennies and you have nine pennies, and we put them all together you'd have 18. Just count like before ^

Hope this helps!
Solnce55 [7]3 years ago
5 0
Often with regrouping of 2 numbers then counting them once all together
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Answer:

  • square: 12 ft sides
  • octagon: 6 ft sides

Step-by-step explanation:

This problem can be worked in your head.

If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.

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We can let s represent the side length of the octagon. Then we have ...

  8s = perimeter of octagon

  4(s +6) = perimeter of square

These are equal, so ...

  4(s +6) = 8s

  s +6 = 2s . . . . . . divide by 4

  6 = s . . . . . . . . . . subtract s

The octagon has 6-ft sides; the square has 12-ft sides.

8 0
3 years ago
Which of the following points are more than 5 units from the point P(−2, −2)? Select all that apply. A A (2, 1) B B (4, −1) C C
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The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

<span> |PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}</span></span>


Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.


|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5

|PB|= \sqrt{ (-2-4)^{2} + (-2+1)^{2}}= \sqrt{36+1}= \sqrt{37} \approx 6

|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4

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|PE|= \sqrt{ (-2+5)^{2} + (-2-1)^{2}}= \sqrt{9+9}= \sqrt{16}=4


Answer: B and D





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3 years ago
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Steps to solve:

x - 5 for x = 15

~Substitute

15 - 5

~Subtract

10

Best of Luck!

4 0
3 years ago
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What is the x? please answer!
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Answer:

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Step-by-step explanation:

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2. subtract x from the right side to isolate x onto one side

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3. subtract 9 from the left side

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4. divide both sides by 8 to get x alone

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