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Rama09 [41]
3 years ago
5

How do you add single digit numbers

Mathematics
2 answers:
Vaselesa [24]3 years ago
6 0
Hi there!

This question isn't too hard.

To add with single digit numbers you just need to count.

You can regroup too, depending on what numbers you're using. I can give you some examples if you'd like!

1 + 2 = 3 because you need to just count. If I have one apple and you have two, count to see how many apples we have altogether. In this case, we have three apples.

What about 9 + 9? You would regroup because our answer is bigger than ten. If I have nine pennies and you have nine pennies, and we put them all together you'd have 18. Just count like before ^

Hope this helps!
Solnce55 [7]3 years ago
5 0
Often with regrouping of 2 numbers then counting them once all together
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Express in the form n:1 give n as a decimal 21:12
Makovka662 [10]

1.75:1 which is similar to n:1 where n=1.75

<u>Step-by-step explanation:</u>

Here we have to Express in the form n:1 give n as a decimal 21:12 . Let's find out:

Given ratio as 21:12 . Let's convert it into n:1 , where n is decimal

⇒ 21:12

⇒ \frac{21}{12}

⇒ \frac{3(7)}{3(4)}

⇒ \frac{7}{4}

⇒ \frac{\frac{7}{4}}{\frac{4}{4}}                      { dividing denominator & numerator by 4 }

⇒ \frac{\frac{7}{4}}{1}

⇒ \frac{1.75}{1}

⇒ 1.75:1 which is similar to n:1 where n=1.75

7 0
4 years ago
500 tickets were sold for a game for a total of $862.50. If adult tickets sold for $2.00 and children's tickets sold for $1.50,
Alexxandr [17]
You can work these in your head if you consider the revenue generated by the least contributor (children's tickets) and the difference in revenue between that and the larger contributor ($2.00 -1.50 = 0.50).

If all were children's tickets, the revenue would be 500*$1.50 = $750.00. The actual revenue exceeded that amount by $862.50 -750.00 = 112.50. This difference in revenue is made up by the sale of $112.50/$0.50 = 225 adult tickets. Then the number of children's tickets is 500 -225 = 275.

225 adult tickets were sold
275 children's tickets were sold.

_____
If you need an equation, you can write an equation using a variable for the number of adult tickets sold (the largest contributor).
.. (500 -a)*1.50 +a*2.00 = 862.50
.. 0.50a = (862.50 -750.00) . . . . . does this look familiar, yet?
.. a = 112.50/0.50 = 225
6 0
4 years ago
Point p was rotated about the origin (0,0) by -15 degrees.<br><br> Which point is the image of P?
Airida [17]

Answer:

the answer is d.

Step-by-step explanation:

8 0
3 years ago
Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

0.07\sqrt{n} = 1.2996

\sqrt{n} = \frac{1.2996}{0.07}

\sqrt{n} = 18.5658

(\sqrt{n})^{2} = (18.5658)^{2}

n = 345

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
3 years ago
What is 57,910,000 in scientific notation
Alexandra [31]
Are there options to this?
5 0
3 years ago
Read 2 more answers
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