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stiv31 [10]
4 years ago
14

Find the perimeter of the polygon with the vertices g(2, 4), h(2,−3), j(−2,−3), g(2, 4), h(2,−3), j(−2,−3), and k(−2, 4)k(−2, 4)

.
Mathematics
1 answer:
Julli [10]4 years ago
7 0
<span>The distance between g and h is sqrt[(2-2)^2+(4+3)^2]=7 The distance between h and j is sqrt[(2+2)^2+(-3+3)^2]=4 The distance between j and k is sqrt[(-2+2)^2+(-3-4)^2]=7 The distance between k and g is sqrt[(-2-2)^2+(4-4)^2]=4 The perimeter of the polygon is 7+4+7+4=22</span>
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H(x)=1/8x^3-x^2<br><br> Over which interval does h have a positive average rate of change?
lara31 [8.8K]

Answer:

(-\infty,0)\cup(\frac{16}{3},\infty)\\That \ is x\frac{16}{3}

Step-by-step explanation:

h(x)=\frac{1}{8}x^{3} -x^{2} \\\\Differentiate \ h(x) \ with \  respect \ to \ x\\h'(x)=\frac{3}{8}x^{2} -2x

For positive rate of change h'(x)>0

\frac{3}{8} x^{2} -2x>0\\x(\frac{3}{8}x-2)>0\\\\ When \ x0 \ (multiplication \ of \ two \ positives \ is \ positive)\\\\h'(x)>0 \ when \ x\frac{16}{3} \\\\

6 0
4 years ago
A grocery store sells a 7 oz bag of raisins for $1.10 and a 9 oz bag of raisins for $1.46. which size bag has the lower price pe
Marysya12 [62]
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5 0
4 years ago
Read 2 more answers
Which expression is equivalent to the quantity five raised to the negative second power times three raised to the fifth power en
serg [7]

The equivalent expression is 5^(4) * 3^(-10)

<h3>How to determine the equivalent expression?</h3>

The statement is given as:

five raised to the negative second power times three raised to the fifth power end quantity all raised to the negative second power

Rewrite properly as:

(5^-2 * 3^5)^-2

Expand the expression by multiplying the exponents

So, we have:

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Evaluate the products

5^(4) * 3^(-10)

Hence, the equivalent expression is 5^(4) * 3^(-10)

Read more about expression at

brainly.com/question/723406

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Answer:

i think its 96 dollars

Step-by-step explanation:

600 × .06 = 24

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