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2 years ago

Determine if direct variation x-2y=0

Mathematics

1 answer:

Fofino [41]2 years ago

3 0

Answer:

x-2y=0 is a direct variation

Step-by-step explanation:

Direct variation is of the form

y= kx

Can we get the equation in that form

x-2y =0

Add 2y to each side

x-2y+2y =0_2y

x=2y

Divide each side by 2

x/2 = 2y/2

1/2x =y

Flip the sides

y = 1/2x

This is of the form y= kx where k = 1/2

x-2y=0 is a direct variation

You might be interested in

Write 420 as a product 9f prime numbers

stich3 [128]

Answer:

2, 2, 3, 5, 7 that is the farthest you can go

Step-by-step explanation:

2,2,3,5,7 prime factorization of 420 but impossible to get 9 factors

5 0

2 years ago

(1+y) (4y+6) =0 algebra 2

marta [7]

Here is your answer! Hope this helped

5 0

2 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

-74 + 36.2=<br> Step by step

My name is Ann [436]

Step-by-step explanation:

-74+36.2=-37.8

I hope it will help you

3 0

3 years ago

Read 2 more answers

At a given time of the day, the ratio of the height of an object to the length of its shadow is the same for all objects. If a 3

Lubov Fominskaja [6]

Answer:

20.3 ft

Step-by-step explanation:

The object-shadow ratio for the stick= 3÷1.5=2:1

The object-shadow ratio is same for all objects.

Let height of the tree be x

2/1 = x/10.15

x=10.15 * 2=20.3

4 0

3 years ago