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ArbitrLikvidat [17]
1 year ago
11

A bowling alley charges $15 per game. Customers are not charged to rent bowling shoes.

Mathematics
1 answer:
Dimas [21]1 year ago
8 0

The description shows a linear relationship and a proportional relationship.

<h3>How to describe the given relationship?</h3>

The given parameters are:

Charger = $15 per game

Customers are not charged to rent bowling shoes.

The statement "Customers are not charged to rent bowling shoes" means that the linear function has no y-intercept

So, the linear function can be represented as

y = Charges * x

This gives

y = 15x

Linear functions that are proportional functions are represented as y = mx

In this case, y = mx represents y = 15x

Hence, the description shows a linear relationship and a proportional relationship.

Read more about proportional relationship at

brainly.com/question/12242745

#SPJ1

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andrey2020 [161]
The answer is linked below
8 0
2 years ago
PLEASE HELP
Savatey [412]
Correct Answer: Option A

The next step in simplification will be to convert the squared term so that it no longer contains a square.

So, we are to simplify the term cos^{2}(2x)

Using the half-angle identity we can write:

cos^{2}(2x)= \frac{1+cos(4x)}{2}

Using this value, the equation becomes:

sin^{4}x=1-2cos(2x)+ \frac{ \frac{1+cos(4x)}{2} }{4}

Therefore, option A is the correct answer.
4 0
3 years ago
Shaun collects coins. He has 18 quarters and 24 pennies in a jar. What is the ratio of quarters to pennies in a jar?
Nutka1998 [239]

Answer:

18:24 or simplest form is 3:4

Step-by-step explanation: If you don't need to simplify then it is 18:24, but if you simplify it by dividing 18 and 24 by 6, then the answer is 3:4 :)

5 0
3 years ago
Read 2 more answers
The thickness of each type of coin is shown in the table. How much thicker is a stack of a dollars worth of nickels than a dolla
il63 [147K]

Answer:

16 nickels thicker

Step-by-step explanation:

You would need 20 nickels for 1 dollar and only 4 quarters for 1 dollar.  Do 20 minus 4 and your answer is 16 nickels. The stack of nickels is 16 coins thicker. Hope this helped!

5 0
3 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
2 years ago
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