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worty [1.4K]
3 years ago
13

1. The three salespeople for a local advertising firm are Sara, Kenny, and Leila. Sara sold $3350 in ads, Kenny sold $1368, and

Leila sold $456.
(a) What fraction of the total sales did each salesperson sell? Show all of your work.
Mathematics
1 answer:
Dominik [7]3 years ago
4 0

Answer:

\text{Fraction of Sara sold }= \dfrac{1675}{2587}

\text{Fraction of Kenny sold }= \dfrac{684}{2587}

\text{Fraction of Leila sold }= \dfrac{228}{2587}

Step-by-step explanation:

The three salespeople for a local advertising firm are sara, Kenny and Leila.

Sara sold total ads = $3350

Kenny sold total ads = $1368

Leila sold total ads = $456

First we calculate total sale of all three = 3350 + 1368 + 456 = $5174

We need to find fraction of total sale with each person sell.

\text{Fraction of Sara sold }=\dfrac{\text{Sara total sold}}{\text{Total sale by all three}}

\text{Fraction of Sara sold }=\dfrac{3350}{5174}\Rightarrow\dfrac{1675}{2587}\approx 64.75\%

\text{Fraction of Kenny sold }=\dfrac{\text{Kenny total sold}}{\text{Total sale by all three}}

\text{Fraction of Kenny sold }=\dfrac{1368}{5174}\Rightarrow\dfrac{684}{2587}\approx 26.45\%

\text{Fraction of Leila sold }=\dfrac{\text{Leila total sold}}{\text{Total sale by all three}}

\text{Fraction of Leila sold }=\dfrac{456}{5174}\Rightarrow\dfrac{228}{2587}\approx 8.8\%

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3 years ago
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asambeis [7]

Answer:

a) From A ∩ A' = ∅, we have;

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b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B)  = (A ∩ B) (Addition to zero identity property)

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(A ∪ B)' = A' ∩ B'

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A ∩ (A ∪ B)' = ∅.

4 0
3 years ago
How do I solve this?
meriva
Hello,

If 3x-1>=0 then

x>=1/3
|3x-1\=3x-1
2*|3x-1|=18
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else
x<1/3
|3x-1|=-(3x-1)
2*|3x-1|=18
2(-(3x-1))=18
-6x+2=18
-6x=16
x=-8/3
endif


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