Answer:
c) growth of the cell and replication of DNA prepare the cell for division
I think the correct answer from the choices listed above is option B. Keratin is the protein in mammals which shows only a primary and secondary structure. Keratin is a fibrous protein forming the structural constituent of hair, feathers, hoofs, claws and many others.
Answer:
Look like palm trees
Explanation:
Cycads are an ancient group of seed plants with a crown of large compound leaves and a stout trunk. They are a minor component of the flora in tropical and subtropical regions today, but during the Jurassic Period, they were a common sight in many parts of the world.
While on the other hand,
The Pinophyta, also known as Coniferophyta or Coniferae, or commonly as conifers, are a division of vascular land plants containing a single extant class, Pinopsida. They are gymnosperms, cone-bearing seed plants. All extant conifers are perennial woody plants with secondary growth.
Answer:
clustered distribution (clumped)
Explanation:
In ecology, species distribution refers to the way in which a biological taxon is spatially arranged in a particular geographic area. Species patterns of distribution are fundamental to analyze ecological systems. The main distribution patterns include 1-clustered (clumped) distribution, 2-uniformed distribution, and 3-randomized distribution. The clustered distribution is the most common type of dispersion pattern in nature and occurs when species tend to form small sets of three or more individuals clustered together. A clustered distribution may be due, for example, when resources (e.g., water) are not evenly distributed in the environment (unequal distribution of the resources). Moreover, a uniform distribution occurs organisms keep a uniform, constant, distance from each other (e.g., due to competition for limited resources), while a randomized distribution occurs when individuals are randomly distributed because resources are not limited.
Answer:
t = ln (N/N°)/(-0.0239)
Explanation :
The decay law is represented as
N = N°e^-kt
Where N is the final number of atom,
N° is the initial number of atoms
k is the decay constant
t is the half-life.
From the above we have,
N/N° = e^-kt
take ln of both sides
ln (N/N°) = -kt
t = ln(N/N°)/-k
At half life, N/N° = 1/2
Therefore, t = (ln 1/2)/-k
t = -0.693/-k
But t = 29 sec
29 = -0.693/-k
k = 0.0239 s^-1
Therefore,
The formula will be
t = ln (N/N°)/(-0.0239)
