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taurus [48]
3 years ago
7

Is it possible for a quadrilateral to have only 2 right angles

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
8 0
A quadrilateral<span> is a square if and </span>only<span> if it is both a rhombus and a rectangle (four equal sides and four equal </span>angles<span>). So, I would think that no, they can't have 2 right angles. </span>
snow_tiger [21]3 years ago
6 0
Yes. An example of this would be a right angled trapezoid 

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using the two variables linear equation x-2y=6. Find the missing coordinate (4, ). Then write the ordered pair for the solution.
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Answer:

72+40

Step-by-step explanation:

9(8+5) 8(9+5 8(9+7 5(8+9)

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There are 10 books on a shelf of which 4 are paperbacks
kow [346]
Explain more please
8 0
3 years ago
Christine has $875.83 In her savings account the account pays 9% compounded monthly. Christine does not make any deposits or wit
Karolina [17]

Answer: the account earns interest of $40.16

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

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P represents the principal or initial amount deposited

From the information given,

P = 875.83

r = 9% = 9/100 = 0.09

n = 12 because it was compounded 12 times in a year.

t = 6 months = 6/12 = 0.5 year

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A = 875.83(1+0.09/12)^0.5 × 12

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A = 875.83(1.0075)^6

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7 0
3 years ago
Is the opposite of -72, positive 72?
fiasKO [112]

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3 0
3 years ago
I need help with this problem , GEOMETRY
34kurt

k:\ y=m_1x+b_1\\l:\ y=m_2x+b_2\\\\k\ ||\ l\iff m_1=m_2\\\\k\ \perp\ l\iff m_1m_2=-1

1.\\(-6,\ 1),\ (0,\ -2)\\\\m_1=\dfrac{-2-1}{0-(-6)}=\dfrac{-3}{6}=-\dfrac{1}{2}\\\\(0,\ 3),\ (4,\ 1)\\\\m_2=\dfrac{1-3}{4-0}=\dfrac{-2}{4}=-\dfrac{1}{2}\\\\m_1=m_2\\\\Answer:\ Parallel


(-4,\ 0),\ (2,\ 4)\\\\m_1=\dfrac{4-0}{2-(-4)}=\dfrac{4}{6}=\dfrac{2}{3}\\\\(-3,\ 4),\ (1,\ -2)\\\\m_2=\dfrac{-2-4}{1-(-3)}=\dfrac{-6}{4}=-\dfrac{3}{2}\\\\m_1m_2=\dfrac{2}{3}\cdot\left(-\dfrac{3}{2}\right)=-1\\\\Answer:\ Perpendicular

5 0
2 years ago
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