Answer:
The mass in grams of one mole of a substance.
Given what we know, we can confirm that option A is correct in that Stronger IMFs lead to stronger adhesion, producing rounder drops with a smaller diameter.
<h3>What are IMFs?</h3>
IMF is the acronym used to describe intermolecular forces. These forces include all of the forces that bind molecules together, of which water has plenty. This bonding force creates a high adhesion and thus gives water its surface tension which makes it stay together in the shape of a drop.
Therefore, we can confirm that stronger IMFs lead to stronger adhesion, producing rounder drops with a smaller diameter, and therefore that option A is correct.
To learn more about molecular forces visit:
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Answer
Naphthalene is a non electrolyte
If the unknown compound is an electrolyte it gives 2 or more ions in solution
( NaCl >> Na+ + Cl- => 2 ions
Ca(NO3)2 >> Ca2+ + 2 NO3- => 3 ions)
the f.p. lowering is directly proportional to the molal concentration of dissolved ions in the solution )
For naphthalene
delta T = 1.86 x m
for a salt that gives 2 ions
delta T = 1.86 x m x 2
hence the lowering in freezion point of unkown is greater then napthalene
Answer:
Molecular formula = C₂H₆
Explanation:
Given data:
Percentage of hydrogen = 20.0 %
Percentage of carbon = 80.0 %
Molar mass = 30.0 g
Empirical formula = ?
Solution:
Number of gram atoms of H = 20 / 1.01 = 19.8
Number of gram atoms of C = 80 /12 = 6.7
Atomic ratio:
C : H
6.7/6.7 : 19.8/6.7
1 : 3
C : H = 1 : 3
Empirical formula is CH₃.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula = CH₃ = 12×1 +3×1.01 = 15.03 g/mol
n = 30 g/mol / 15.03 g/mol
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 (CH₃)
Molecular formula = C₂H₆
Metals nonmetals and Metalloids is the answer
