Why must we use the kelvin scale in gas laws
2 answers:
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We know that the equation for density is:
where D is the density, m is the mass in grams, and V is the volume.
Given two of the variables, we can then solve for density:
Therefore, we now know that the density of the gasoline is 0.833g/mL.
Answer:
Explanation:
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In this case, since the combustion of butane is:
Thus, since the molar mass of butane is 58.12 g/mol and that of carbon dioxide is 44.01 g/mol, we obtain the following mass of CO2 product:
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