Answer:
Stock solution = 1.25 *10^-3 M
Dilution 1 = 5*10^-4 M
Dilution 2= 3.75 * 10^-4 M
Dilution 3 = 2.5 *10^-4 M
Dilution 4 = 1.25 *10^-4 M
Explanation:
<u>Step 1:</u> Data given
The stock solution is made by diluting 5.00 ml of 1.250 x 10-2 M salicylic acid in 50.00 mL of solution.
<u>Step 2</u>: Calculate the concentration of the stock solution:
M1*V1 = M2*V2
⇒ with M1 = the initial concentration = 1.250 *10^-2 M
⇒ with V1 = 5 mL = 5*10^-3 L
⇒ with M2 = TO BE DETERMINED
⇒ with V2 = 50 mL = 50 *10^-3 L
M2 = (M1*V1)/V2
M2 = (1.250 *10^-2 * 5*10^-3 L) / 50 *10^-3
M2 = 0.00125 M = 1.25 *10^-3 M
<u>Step 3:</u> Calculate dilution 1
M2 = (M1*V1)/V2
M2 = (1.25*10^-3 * 10 *10^-3)/(25*10^-3L)
M2 = 0.0005 M = 5*10^-4 M
<u>Step 4</u>: Calculate dilution 2
M2 = (M1*V1)/V2
M2 = (1.25*10^-3 * 10 * 7.5*10^-3)/(25*10^-3)
M2 = 0.000375 M = 3.75 * 10^-4 M
<u>Step 5:</u> Calculate dilution 3
M2 = (M1*V1)/V2
M2 = (1.25*10^-3 * 5*10^-3) /(25*10^-3)
M2 = 0.00025 M = 2.5 *10^-4 M
<u>Step 6</u>: Calculate dilution 4
M2 = (M1*V1)/V2
M2 = (1.25*10^-3 * 2.5*10^-3)/(25*10^-3)
M2 = 0.000125 M = 1.25 *10^-4 M
