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Ne4ueva [31]
3 years ago
12

Why must we use the kelvin scale in gas laws

Chemistry
2 answers:
Vinil7 [7]3 years ago
4 0
The Kelvin scale<span> is </span>used<span> in </span>gas law<span> problems because the pressure and volume of a</span>gas<span> depend on the kinetic energy or motion of the particles. The </span>Kelvin scale<span> is proportional to the KE of the particles</span>
goldenfox [79]3 years ago
3 0
The Kelvin scale<span> is </span>used<span> in </span>gas law problems because the pressure and volume of gas<span> depend on the kinetic energy or motion of the particles. The </span>Kelvin scale<span> is proportional to the KE of the particles… that is, 0 K (absolute zero) means 0 kinetic energy. 0 °C is simply the freezing point of water. Hope this Helps researched it from a site</span>
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What is the theoretical yield of fluorenone if you oxidize 175 mg of fluorene?
My name is Ann [436]

Answer:

  • 602 mg of CO₂ and 94.8 mg of H₂O

Explanation:

The<em> yield</em> is measured by the amount of each product produced by the reaction.

The chemical formula of <em>fluorene</em> is C₁₃H₁₀, and its molar mass is 166.223 g/mol.

The <em>oxidation</em>, also know as combustion, of this hydrocarbon is represented by the following balanced chemical equation:

        2C_{13}H_{10}+31O_2\rightarrow 26CO_2+10H_2O

To calculate the yield follow these steps:

<u>1. Mole ratio</u>

          2molC_{13}H_{10}:31molO_2:26molCO_2:10molH_2O

<u />

<u>2. Convert 175mg of fluorene to number of moles</u>

  • 175mg/times 1g/1,000mg=0.175g

  • Number of moles = mass in grams / molar mass

  • \text{number of moles}=0.175g/166.223g/mol=0.0010528mol

<u>3. Set a proportion for each product of the reaction</u>

a) <u>For CO₂</u>

i) number of moles

         2molC_{10}H_{13}/26molCO_2=0.0010528molC_{10}H{13}/x

x=0.0010528molC_{10}H_{13}\times 26molCO_2/2molC_{10}H_{13}=0.013686molCO_2

ii) mass in grams

The molar mass of CO₂ is 44.01g/mol

  • mass = number of moles × molar mass
  • mass = 0.013686 moles × 44.01 g/mol = 0.602 g = 602mg

b) <u>For H₂O</u>

i) number of moles

0.0010528molC_{10}H_{13}\times10molH_2O/2molC_{10}H_{13}=0.00526molH_2O

ii) mass in grams

The molar mass of H₂O is 18.015g/mol

  • mass = number of moles × molar mass
  • mass = 0.00526 moles × 18.015 g/mol = 0.0948mg = 94.8 mg
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