Alkaline earth metal are the elements present in II group in the periodic table and are known as 'Metals' and have a charge of +2.
Alkaline earth metals - Be , Mg Ca, Sr , Ba, Ra
Halogens are present in VII A group in the periodic table and are 'Non-metals' and have a charge of -1.
Halogens - F, Cl, Br, I, At
When Alkaline earth metal (metals) combine with Halogens (non-metals) the compound formed will be ionic compound and the formula of the compound will be based on the charges of the element.
When we write the formula of the ionic compound the charges of the elements get criss crossed.
For example - Mg (Alkaline earth metal) have a charge of +2 and Cl (Halogen) have a charge of -1 and when they combine to form the formula their charges get criss crossed and we will get 
or 
When an alkaline earth metal, A, reacts with a halogen, X, the formula of the Ionic compound formed should be 
Answer:
The correct option is False
Explanation:
Ionization energy is the <em>minimum amount of energy required to remove a valence electron from one mole of an atom in it's gaseous state</em>. Ionization energy requires the removal of an electron from a gaseous atom. The definition in the question is that of electronegativity.
Electronegativity is the <u>ability of an atom to attract electrons towards itself in a chemical bond.</u>
#1. An element or ion that has lost two electrons must have a net charge of 2+, because it has two more protons than electrons, therefore the answer is Mg2+
#2. aluminum ions have an oxidation state of 3+ and fluoride has an oxidation state of 1-, therefore I’m order for the charges to cancel you need 3 fluoride ions.
Therefore, the answer is AlF3
<h3>
Answer:</h3>
11.84 mol CoF₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
- Analyzing Reactions RxN
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Unbalanced] CoCl₂ + F₂ → CoF₂ + Cl₂
[RxN - Balanced] CoCl₂ + F₂ → CoF₂ + Cl₂
[Given] 11.84 moles CoCl₂
[Solve] moles CoF₂
<u>Step 2: Identify Conversions</u>
[RxN] 1 mol CoCl₂ → 1 mol CoF₂
<u>Step 3: Stoich</u>
- [DA] Set up:
- [DA] Multiply/Divide [Cancel out units]:
If the question includes x only than it’s value would be 1
